Answer:
Explanation:
Height attained by body = 50 cm
= .5 m
Initial velocity = u
v² = u² - 2gh
0 = u² - 2gh
u² = 2 x 9.8 x .5
u = 3.13 m /s
During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .
v² = u² + 2as
3.13² = 0 + 2 a x .10
a = 49 m/s²
reaction by ground R
Net force
R-mg = ma
R= m ( g +a )
= mg + ma
=W + (W/g) x a
W ( 1 + a / g )
= W ( 1 + 49 / 9.8 )
= 6W
Answer:
D. Ted expanded more power.
Explanation:
Given the following data;
For Ted.
Force = 10N
Height = 1.5m
Time = 1 seconds
To find Ted's power;
Power = workdone/time
But workdone = force * distance
Workdone = 10 * 1.5
Workdone = 15 Nm
Power = 15/1
Power = 15 Watts.
For Johnny.
Force = 10N
Height = 1.5m
Time = 2 seconds
To find Ted's power;
Power = workdone/time
But workdone = force * distance
Workdone = 10 * 1.5
Workdone = 15 Nm
Power = 15/2
Power = 7.5 Watts
Therefore, from the calculations we can deduce and conclude that Ted expanded more power.
Answer:
d = 69 .57 meter
Explanation:
First case
Speed of car ( v ) = 20.5 mi/h = 9.164 M/S
distance ( d ) = 11.6 meter ( m = mass of the car )
Work done = 0.5 m v² = 0.5 * 9.164² * m J = 41.99 m J
Force = ( workdone /distance ) = ( 41.99 m / 11.6 ) = 3.619 m N
Second case
v = 50.2 mi/h = 22.44135 m/s
d = ?
Work done = 0.5 * 22.44² * m J = 251.7768 * m J
Since the braking force remains the same .
3.619 m = ( 251.7768 m / d )
d = 69 .57 meter
Momentum equation is
change in momentum = mass•initial velocity•final velocity
so....
p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!
An earthquake or disturbance undersea.
~ThePirc
