Answer:
Explanation:
NaNO₃ = Na⁺ + NO₃⁻¹
.497 M .497 M
moles of NO₃⁻¹ = .897 x .497 = .4458 moles
Ca( NO₃)₂ = Ca + 2 NO₃⁻¹
.341 M 2 x .341 M = .682 M
moles of NO₃⁻¹ = .813 x .682 = .5544 moles
Total moles = .4458 moles + .5544 moles
= 1.0002 moles
volume of solution = 897 + 813 = 1710 mL
= 1.710 L
concentration of nitrate ion = 1.0002 / 1.710 M
= .585 M
Answer:
CH4+2O2→CO2+2H2O
Moles of oxygen=3232=1
Moles of carbon dioxide=4422=0.5
Moles of water=1818=1
1 mole of methane reacts with 2 moles of oxygen to give 1 mole of CO2 and 2 moles of water so 0.5 mole of methane will be required which is equal to 0.5×16=8g.
Explanation:
8g
3.54g H2 means you have 3.54 / 2 = 1.77 moles of H2, which means you have 1.77*2 = 3.54 moles of H atom.
Since 1 mole of NH3 has 3 moles of H, so you can produce 3.54 / 3 moles of NH3, which is (3.54/3) * (12+3) = 17.7 grams
Answer:
4.27 g
Explanation:
We can write that for a gas kept at constant pressure and temperature, the number of moles of the gas is directly proportional to its volume:
Which can be rewritten as
where here we have:
is the initial number of moles
is the initial volume of the gas
is the final volume of the gas
So the final number of moles is
So the number of moles that should be released from the balloon is:
The molar mass of gas N2 is
Therefore, the mass of gas that should be released is:
Answer:
3.0002 moles
Explanation:
Data Given:
mass of NO₂ = 138.01 g
No. of moles NO₂ = ?
Solution
To find mass of sample mole formula will be used
mole formula
no. of mole = mass in grams / molar mass
Molar mass of NO₂ = 14 + 2(16)
Molar mass of NO₂ = 14 + 32 = 46 g/mol
Put values in above equation
no. of mole = 138.01 g / 46 g/mol
no. of mole = 3.0002 moles
no. of mole of NO₂ = 3.0002 moles
