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igomit [66]
2 years ago
8

4. Think of the solids and liquids that you encounter every day. In what ways are solids and liquids similar? In what ways are t

hey different?​
Chemistry
1 answer:
Taya2010 [7]2 years ago
3 0

Answer:

They both are the same thing which is water but they are just in different forms.

Explanation:

A solid is water that is frozen and a liquid is just water.

You might be interested in
Is milk a mixture, solution, or both?
lara [203]
It is both. It is a mixture because it has two or more things mixed in it. It is a solution, because all of the components and things mixed in the milk are uniform and milk isn't chunky or discolored because of that.
Hope this helps. 
5 0
3 years ago
Read 2 more answers
What is the volume of 1.50 lb (pounds) of mercury? The density of mercury is 13.546 g/mL. Use the conversion that 1 kg = 2.20 lb
Arada [10]

Answer:

50.3mL of mercury are in 1.50lb

Explanation:

Punds are an unit of mass. To convert mass to volume we must use density (13.546g/mL). Now, As you can see, density is in grams but the mass of mercury is in pounds. That means we need first, to convert pounds to grams to use density and obtain volume of mercury.

<em>Mass mercury in grams:</em>

1.50lb * (1kg / 2.20lb) = 0.682kg = 682g of mercury.

<em>Volume of mercury:</em>

682g Mercury * (1mL / 13.546g) =

<h3>50.3mL of mercury are in 1.50lb</h3>
7 0
4 years ago
A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon
Gekata [30.6K]

Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

n₂ = 0.683 moles of the gas are required

<em />

8 0
3 years ago
What is the number of molecules present in 1.12 dm^3 of nitrogen gas at STP​
Anuta_ua [19.1K]

Answer:

\huge\boxed{\sf No.\ of\ molecules = 3 * 10\²\² \ molecules}

Explanation:

<u>Given Data:</u>

Volume = v = 1.12 dm³ = 1.12 L

Density of nitrogen at STP = D = 1.25 g / L

Molar mass = M = 14 * 2 = 28 g / mol

Avogadro's Number = \tt{N_{A}} = 6.023 * 10²³ mol⁻¹

<u>Required:</u>

No. of molecules = ?

<u>Formula:</u>

\tt{No. \ of \ molecules = \frac{Density * Volume}{Molar\ Mass} * N_{A}}

<u>Solution:</u>

No. of molecules = (1.25*1.12) / 28 * (6.023 * 10²³)

No. of molecules = ( 1.4 / 28 ) * 6.023 * 10²³

No. of molecules = 0.05 * 6.023 * 10²³

No. of molecules = 0.3 * 10²³

No. of molecules = 3 * 10²² molecules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
100.-gram sample of H2O() at 22.0°C absorbs 8360 joules of heat. What will be the final temperature of the water?
nexus9112 [7]
_Award brainliest if helped!
Assume Specific Heat capacity of water = 4.186 J/g<span>°C
100g sample, 
Q=mc</span>Δθ<span>
8360=100(4.186)(Final Temp.-22.0)
Final Temperature </span>≈<span>41.97</span><span>°C</span>
8 0
3 years ago
Read 2 more answers
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