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3 years ago

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there are two equivalent fractions that have a least common denominator of 14. the sum of both of the denominators is 56. the su

m of both of the numerators is 12. the smaller numerator is over the smaller denominator. what are these two equivalent fractions brainly

1 answer:

777dan777 [17]3 years ago

7 0

Answer:

11+2=

Step-by-step explanation:

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Scott has 1/3 of the computer games as Anish, and Anish has 1/2 as many games as Nick. Together they have 140 games. How many do

Contact [7]

Let x = # of computer games nick has
then
Anish has 1/2x games
and
Scot has 1/2*1/3 = 1/6x games
thus
1/6x + 1/2x + x = 140
1/6x + 3/6x + x = 140
10/6x = 140
10x =140* 6
x = 84 > Nick
1/2x = 42 > Anish
1/6x = 14 > Scot

4 0

3 years ago

Read 2 more answers

Help 9-11 thank you !

krok68 [10]

Answer:

9 - 11 = -2

Step-by-step explanation:

Because 9 is being subtracted by a number greater than itself, the answer has to be a negative and because:

9 + 2 = 11

9 - 11 = (-2)

Your Welcome :)

7 0

3 years ago

WILL MARK BRAINLIEST!!

Snowcat [4.5K]

15/10 = 18-x/x is the ratio of the larger to the smaller triangle

Cross multiply:
15x = 10(18 - x)
15x = 180 - 10x
25x = 180
x = 7.2

Plug back in to check
15/10 = 1.5

18-7.2/7.2 = 10.8/7.2 = 1.5 :)

6 0

3 years ago

Jamal is a door to door vacuum salesman. His weekly salary, S , is $250 plus $50 for each vacuum he sells. This can be written a

Aleks04 [339]

Answer:

31 vacuums

Step-by-step explanation:

1800 = 250 + 50v

1800 - 250 = 50v

50v = 1550

v = 1550 / 50

v = 31

He sold 31 vacuums.

8 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago