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vova2212 [387]
3 years ago
9

(SHOW YOUR WORK) 67.5+23.57

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0
67.5 + 23.57=
91.07
Dima020 [189]3 years ago
7 0

<h2>\:  \: 67.5 \\  +  \underline{23.57} \\ \:  \:  \:  \: \green{\boxed{ 91.07}}</h2>
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PLEASE HELP ME!! (50 COINS) (i rlly need help so im giving coins away PLEASE ANSWER IMMEDIATELY!!!)
Archy [21]

Hello from MrBillDoesMath!

Answer:

4( x + 1.5)^2 + 0  

Discussion:

4x^2 + 12x + 9 =                => factor "4" from first 2 terms

4 (x^2 + 3x) + 9 =               => complete the square, add\subtract (1.5)^2

4(x^2 + 3x + (1.5)^2)  - 4 (1.5)^2 + 9  =

4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) =           => as (1.5)^2 = 2.25

4 ( x + 1.5)^2 + ( 9 - 4(2.25)) =        => as 4 ( 2.25) = 9

4 ( x+ 1.5)^2 + 0


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3 years ago
Find the circumstances of the circle
Mkey [24]
The meaning of circumference is to find the distance around a circle or in other words perimeter by using the formula C=2πr or C=<span>πd.

On this case it is asked you to find the circumference of a circle with a diameter of 3 meters, so you will use the formula C=2</span><span>πr.

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Rainbow [258]

Answer:

x = 6

Step-by-step explanation:

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2 years ago
Helppp me plsssssssss<br><br>​
Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

  • \sf \:\:\:\:\:\:\:\:\:\:x_{k}=35
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k}=50
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34
  • \sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42
  • \sf \:\:\:\:\:\:\:\:\:\:h=5

{\bf \:\: {By\:using\:the\: formula}} \\ \\

\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\

\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\

\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\

\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\

{\large{\frak{\pmb{\underline{Additional\: information }}}}}

MODE

  • Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

  • In a frequency distribution the class having maximum frequency is called the modal class.

{\bf{\underline{Formula\:for\: calculating\:mode:}}} \\

{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\

Where,

\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.

\small \blue{ \bigstar}\sf \: f_{k}=frequency\:of\:the\:modal\:class

\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class

\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class

\small \purple{ \bigstar}\sf \: h= width \:of\:the\:class\:interval

7 0
3 years ago
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