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3 years ago

Write an equation in slope-intercept form perpendicular to the given equation through the given point

Mathematics

1 answer:

Irina18 [472]3 years ago

6 0

Answer:

y = (1/3)x - 4

Step-by-step explanation:

Any line perpendicular to the given equation y = -3x + 4 will have a slope which is the negative reciprocal of -3; that is, +1/3.

Start with the general slope-intercept form y = mx + b.

Insert the coordinates 6 and -2 into y = mx + b: -2 = (1/3)(6) + b, or

-2 = 2 + b. Thus, b = -4, and the desired equation is

y = (1/3)x - 4

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GaryK [48]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

Answer this equation -3(5g+1)+8g=

maksim [4K]

Answer:

-7g - 3

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Combining like terms

Step-by-step explanation:

Step 1: Define expression

-3(5g + 1) + 8g

Step 2: Simplify

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3 years ago

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Solve the equation for all real values of x. sec2x + 2secx = 0

Alecsey [184]

Given :

$sec^2\ x + 2sec\ x = 0$

To Find :

All real value solution of given equation.

Solution :

Simplifying given equation, we get :

sec x( sec x + 2 ) = 0

sec x = 0 and (sec x + 2) = 0

For, sec x = 0 :

x = not defined.

For, (sec x + 2) = 0 :

cos x = -1/2

x = cos⁻¹( -1/2 ) = 2π/3

Therefore, general solution is ( 2nπ ± 2π/3 ), n ∈ Z⁺ .

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3 years ago