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3 years ago

Help needed! no links please, they're annoying.

Mathematics

1 answer:

denis23 [38]3 years ago

4 0

The area of a rectangle is length*width.

The length of this 3x and the width is 2x-3. This means that, to find the area, you need to multiply 3x and 2x-3.

Start by writing out this equation:
A=l*w

Then, plug in your given values:
A= 3x*2x-3 (you can also write it as A= 3*x*2*x-3)

Then, following the order of operations, you start by multiplying. This makes your equation become A = 6x^2 -3. (^2 means squared). It turns into this because 3 * 2 is 6 and x * x is x^2 and you still haven’t used the 3 yet.

After this, there is nothing more that you can do to simplify the equation. Therefore, the area is 6x^2 - 3.

I hope this helped!

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

Can someone help please asap

ch4aika [34]

Sn = (a1) x (1 - r^n) / (1 - r)

Substituting the known values:

S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9

3 0

3 years ago

Need help pleaseee i have a test on friday

larisa [96]

Answer:

x = 8

Step-by-step explanation:

Using the sine or cosine ratio in the right triangle and the exact value

sin30° = $\frac{1}{2}$ , then

sin30° = $\frac{opposite}{hypotenuse}$ = $\frac{4}{x}$ = $\frac{1}{2}$ ( cross- multiply )

x = 8

5 0

3 years ago

Four gallons of paint cost $49.44. Which equation can be used to find c, the cost per gallon?

natulia [17]

<span>Four gallons of paint cost $49.44. <span>Which equation can be used to find c, the cost per gallon?
c=$49.44/4
c= $12.36 per gallon</span></span>

5 0

3 years ago

A small plane circles the airport at Daniel Field at 1500 feet altitude before starting to land. If the airport runway is 10,000

klio [65]

Small plane circles the airport the angle of depression would be 180

7 0

3 years ago