There is no picture attached so not sure what you are talking about
Answer:
c. g(x) = 4x^2
Step-by-step explanation:
From a first glance, since g(x), is skinnier than f(x), meaning that it is increasing faster, so I know that I can eliminate options A & B since the coefficient on x needs to be greater than 1.
We can then look and see that g(1) = 4 as shown by the point given to us on the graph.
To find the right answer we can find g(1) for options C & D and whichever one matches the point on the graph is our correct answer. e
Option C:
once we plug in 1 for x, our equation looks like
4(1)^2.
1^2 = 1, and 4(1) = 4,
so g(1) = 4. and our point is (1,4).
This is the same as the graph so this is the CORRECT answer.
If you want to double check, you can still find g(1) for option D and verify that it is the WRONG answer.
Option D:
once we plug in 1 for x, our equation looks like
16(1)^2
1^2 = 1, and 16(1) = 16,
so g(1) = 16. and our point is (1,16).
This is different than the graph so this is the WRONG answer.
Question:
Fill in the blank.
23 x 6 = (20 + 3) * 6
23 x 6 = _ + (3x6)
Options
20 * 6
20 * 3
20 * 5
Answer:
20 * 6
Step-by-step explanation:
Given
Expression 1: 23 * 6 = (20 + 3) * 6
Expression 2: 23 * 6 = __ + (3 * 6)
Required
Fill in the blank
From Expression 1
23 * 6 = (20 + 3)*6
Using Distributive Property; The expression becomes
23 * 6 = 20 * 6 + 3 * 6
23 * 6 = (20 * 6) + (3 * 6)
By Comparing this with expression 2
23 * 6 = __ + (3 * 6)
The blank position is occupied by 20 * 6.
Hence, the correct option that fills the missing blank correctly is 20 * 6
A. The area of a square is given as:
A = s^2
Where s is a measure of a side of a square. s = (2 x – 5) therefore,
A = (2 x – 5)^2
Expanding,
A = 4 x^2 – 20 x + 25
B. The degree of a polynomial is the highest exponent of the variable x, in this case 2. Therefore the expression obtained in part A is of 2nd degree.
Furthermore, polynomials are classified according to the number of terms in the expression. There are 3 terms in the expression therefore it is classified as a trinomial.
<span>C. The closure property demonstrates that during multiplication or division, the coefficients and power of the variables are affected while during multiplication or division, only the coefficients are affected while the power remain the same.</span>
