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Reil [10]
3 years ago
11

The car has a mass of 1200kg. The car has a forward force of 3400N but friction has a force of 400N going against it. What is th

e acceleration of the car?
Chemistry
1 answer:
jonny [76]3 years ago
6 0

The acceleration of the car : 2.5 m/s²

<h3>Further explanation</h3>

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object  

∑F = m. a  

<h3 />

Mass of the car = 1200 kg

Forward force = 3400 N

Friction force = 400 N

The direction of motion of the friction force will be opposite to the forward force, so that both of them can be subtracted to get the value of the net force (net force: combination / sum of all forces acting on an object)

\tt \sum F=3400-400=3000~N

So the acceleration :

\tt a=\dfrac{\sum F}{m}\\\\a=\dfrac{3000}{1200}\\\\a=2.5~m/s^2

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Answer:- 27.7 grams of PbI_2 are produced.

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let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

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