Answer: The molarity of an HCl solution is 0.218 M if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid.
Explanation:
Given: 
= 43.6 mL, 
= 0.125 M
= 25.0 mL, 
= ?
Formula used to calculate the concentration of acid is as follows.
Substitute the values into above formula.
Thus, we can conclude that the molarity of an HCl solution is 0.218 M if 43.6 mL of a 0.125 M NaOH solution are needed to titrate a 25.0 mL sample of the acid.
What class is this for because it depends
Here is 5
Dissolved Load - elements dissolved in solution
Suspended Load - very fine grained sediment such as clay and silt carried in suspension. The size grains that can be carried in suspension are dependent on the current velocity
Wash Load - a subset of the suspension load, extremely small particles (clay) that will remain in suspension independent of turbulence in the river
Saltation Load - particles that are temporarily carried in suspension but move by bouncing along the bottom
<span>Bed Load - sediment that moves by rolling or sliding along the bottom. These are generally the coarser grained sediments such as sand and gravel.</span>
O2 is an example of a molecule
Matematically speaking, maybe because:
The number of substances = number of elements + number of different combinations of those elements
