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bazaltina [42]
3 years ago
5

Three light sticks are activated at the same time. One stick is placed in a beaker of hot water, one in a beaker of ice water, a

nd one remains at room temperature. Which is the likely result? A) The hot stick is brightest, and the cold stick is dimmest. B) The sticks in water are brighter than the one in the room air. C) The hot stick is dimmest, and the cold stick is brightest.
Chemistry
2 answers:
Nuetrik [128]3 years ago
8 0

%%%%%%%%%%%%%%%%%%%%%%%% A.

astra-53 [7]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

It is known that rate of a reaction depends upon temperature. This means that more is the temperature more will be the kinetic energy of particles.

Hence, this will cause greater number of collisions between the particles. As a result, rate of reaction will become faster.

Thus, we can conclude that the result for the given situation will be that the hot stick is brightest, and the cold stick is dimmest.

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A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L.A. If the contai
marta [7]

Answer:

Approximately 6.81 × 10⁵ Pa.

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Explanation:

Look up the relative atomic mass of carbon and oxygen on a modern periodic table:

  • C: 12.011;
  • O: 15.999.

Calculate the molar mass of carbon dioxide \rm CO_2:

M\!\left(\mathrm{CO_2}\right) = 12.011 + 2\times 15.999 = 44.009\; \rm g \cdot mol^{-1}.

Find the number of moles of molecules in that 41.1\;\rm g sample of \rm CO_2:

n = \dfrac{m}{M} = \dfrac{41.1}{44.009} \approx 0.933900\; \rm mol.

If carbon dioxide behaves like an ideal gas, it should satisfy the ideal gas equation when it is inside a container:

P \cdot V = n \cdot R \cdot T,

where

  • P is the pressure inside the container.
  • V is the volume of the container.
  • n is the number of moles of particles (molecules, or atoms in case of noble gases) in the gas.
  • R is the ideal gas constant.
  • T is the absolute temperature of the gas.

Rearrange the equation to find an expression for P, the pressure inside the container.

\displaystyle P = \frac{n \cdot R \cdot T}{V}.

Look up the ideal gas constant in the appropriate units.

R = 8.314 \times 10^3\; \rm L \cdot Pa \cdot K^{-1} \cdot mol^{-1}.

Evaluate the expression for P:

\begin{aligned} P &=\rm \frac{0.933900\; mol \times 8.314 \times 10^3 \; L \cdot Pa \cdot K^{-1} \cdot mol^{-1} \times 298\; K}{3.4\; L} \cr &\approx \rm 6.81\times 10^5\; Pa \end{aligned}.

Apply dimensional analysis to verify the unit of pressure.

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