Answer:
The experimenter observed this experiment in a lab rather than natural world because it might be dangerous to the atmosphere if he does the experiment in the natural world and it was still an hypothesis so that's why he did it in the lab.
Answer:
CH3CH3CH2CH3
Explanation:
Octane is a non-polar compound. It is a hydrocarbon with 8-carbon length along its chain.
It belongs to a special group of hydrocarbons called alkanes.
What makes a substance soluble in another?
It is a common phrase that "like dissolves like". This is applicable to solubility of substances in another.
- A polar solvent will freely and easily dissolve a polar solute. For example, water and salt.
- A non-polar solvent will also dissolve a non-polar solute. This case, hydrocarbons will dissolve themselves.
- The first option is a butane, a 4-carbon length hydrocarbon which will be dissolved in octane.
- Both compounds are non-polar.
<span>Answer:
For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees.
4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ.
Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work.
To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3.
.0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>
