Answer:
96%
Explanation:
Step 1: Write the balanced neutralization reaction
Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O
Step 2: Calculate the theoretical yield of AlCl₃
According to the balanced equation, the mass ratio of Al(OH)₃ to AlCl₃ is 81.03:133.34.
28 g Al(OH)₃ × 133.34 g AlCl₃/81.03 g Al(OH)₃ = 46 g AlCl₃
Step 3: Calculate the percent yield of AlCl₃
The real yield of AlCl₃ is 44 g. We can calculate the percent yield using the following expression.
%yield = real yield / theoretical yield × 100%
%yield = 44 g / 46 g × 100% = 96%
The answer is Didn't
the left side has 2 K and right right side is only one
Answer:
I think the answer is Ar, k or just k. Can you pick two answers?
Explanation:
I hope this helps.
P.S. you put two d's
Answer:
Mass of KOH = 497.78 g
Explanation:
Given data
mass of KOH = ?
number of KOH molecules = 5.34 × 10²⁴
molar mass of KOH = 56.12 g/mol
Solution
1st we find out the number of moles of KOH
<em>number of moles = number of molecules given / Avogadro number
</em>
number of moles of KOH = 5.34 × 10²⁴ / 6.022 × 10²³
number of moles of KOH = 8.87 mol
Now we find out the mass of KOH
<em>Mass of KOH = moles × molar mass</em>
Mass of KOH = 8.87 mol × 56.12 g/mol
Mass of KOH = 497.78 g
Answer:
1.34 moles SO₂(g)
Explanation:
At STP 1 mole of any gas occupies 22.4 Liters. So, for 30 Liters ...
moles SO₂(g) = 30L/22.4L·mol⁻¹ = 1.34 moles SO₂(g)