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tigry1 [53]
3 years ago
14

Use the distributive property then combine any like terms 4(7p+4-2p)

Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

Answer:20p+16

Step-by-step explanation:

Combine like terms

4(7p+4-2p)

4(5p+4)

Distribute

4(5p+4)

20p+16

drek231 [11]3 years ago
3 0

Answer: 20p+16

sorry if this in incorrect please report if im wrong :(

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riadik2000 [5.3K]

Answer:

Dharma and Jorge should purchase a group plan.

They could save $9.55

Step-by-step explanation:

A group plan will cost an average of $135.95 per month.

An individual plan will cost an average of $72.75 per month.

Two individual plans will cost an average of

\$72.75\cdot 2=\$145.50

per month.

Since $145.50 > $135.95,  Dharma and Jorge should purchase a group plan.

They could save

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3 years ago
In a randomly generated list of numbers from 0 to 8 what is the chance thag each number will occur?
Vitek1552 [10]

Answer:

1/9

Step-by-step explanation:

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6 0
3 years ago
What is 4x+3y+2z and 3x+5y+3z?
My name is Ann [436]

Answer:

Step-by-step explanation:

7x + 8y + 5z

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6 0
3 years ago
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The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

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Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
Which statement is true about the dependent and independent variables?
Hatshy [7]

Answer:

1. The independent variable goes on the x-axis and the dependent variable goes on the y-axis.

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