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3 years ago

What is the solution set to this inequality?

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

BING BING BING BING AND JELLY

Maksim231197 [3]3 years ago

7 0

It’s 9 hope this helps

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What property is being illustrated below?<br> 2(7+3)=2(7)+2(3)

AleksAgata [21]

Answer: Associative property

Step-by-step explanation:

8 0

2 years ago

A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

3 0

3 years ago

Can you help me pls, this doesn't make any sense

Gala2k [10]

Area of the larger square = 12² = 144 cm²
Area of the smaller square = 7² = 49 cm²
Area of the section = 144-49 = 95 cm²

7 0

3 years ago

Look at pic plz help

jasenka [17]

Answer:

Mochi

Step-by-step explanation:

Mochi

Each week theres a increase of 4 in Mochi's weight. So you will add 4 twice to get to the 5th week.

4th week : 17

5th week : 21

Kappa

In 4 weeks Kappa weighed 14, which is less that Mochi at the pace Kappa is going at.

on the 3rd week Kappa weighed 11

and 2nd week Kappa weighed 5

and 1st week Kappa weighed 3

Looking at the graph, we can give a rough estimate on the 5th week it's going to be 16 or 17 either way making Mochi heavier.

8 0

2 years ago

Rewrite 7<img src="https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7B2%7D" id="TexFormula1" title="x^{\frac{1}{2}" alt="x^{\frac{1

swat32

Basically, the denominator will always be the number outside of the radical and the numerator will always be your exponent. If it’s one, you don’t put it in because if there is no exponent, it’s an invisible one

8 0

3 years ago

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