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2 years ago

How the choice of building materials and techniques can help them cool down faster, after heating up.

Physics

1 answer:

Sauron [17]2 years ago

3 0

Answer:

The choice of building materials and techniques can help them cool down faster, after heating up is explained below in brief details.

Explanation:

Building materials

Buildings that are composed of rock, bricks, or pavement, or inserted into the territory, can seem cooler thanks to the great "thermal mass" of these elements – that is, their capability to assimilate and discharge heat gently, thereby softening temperatures over time, producing daytime cooler and night-time warmer.

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A planet orbits a star, in a year of length 3.37 x 107 s, in a nearly circular orbit of radius 1.04 x 1011 m. With respect to th

PIT_PIT [208]

Answer

Given,

Time period of star,T = 3.37 x 10⁷ s

Radius of circular orbit,R = 1.04 x 10¹¹ m

a) Angular speed of the planet

$\omega = \dfrac{2\pi}{T}=\dfrac{2\pi}{3.37\times 10^{7}}$

$\omega = 1.864\times 10^{-7}\ rad/s$

b) tangential speed

$v = r \omega = 1.04\times 10^{11}\times 1.864 \times 10^{-7}$

v = 1.94 x 10⁴ m/s

c) centripetal acceleration magnitude

$a = \dfrac{v^2}{r}= \dfrac{(1.94\times 10^4)^2}{1.04\times 10^{11}}$

a = 3.62 x 10⁻³ m/s²

8 0

2 years ago

A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of

ANEK [815]

Answer:

The distance the piece travel in horizontally axis is

L=3.55m

Explanation:

$a=2 \frac{rev}{s^{2}} \\h=0.820m\\r = 0.125 m
\\d=150rev$

$d= 155 rev = 155(2\pi ) = 310\pi rad$

$a= 2.0 \frac{rev}{s^{2} } = 2.0(2\pi ) = 4.0\pi \frac{rev}{s^{2} }$

$d=d_{i}+vo*t+\frac{1}{2}*a*t^{2} \\ di=0\\vo=0\\d=\frac{1}{2}*a*t^{2}\\t=\sqrt{\frac{2*d}{a}}\\t=\sqrt{\frac{2*310 rad}{4\frac{rad}{s^{2}}}} \\t=12.449$

$w=a*t\\w=4\frac{rad}{s^{2}}*12.449s\\ w=49.79 \frac{rad}{s}$

Now the angular velocity is the blade speed so:

$V=w*r\\V=49.79 \frac{rad}{s}*0.175m\\V=8.7 \frac{m}{s}$

assuming no air friction effects affect blade piece:

time for blade piece to fall to floor

$t=\sqrt{\frac{2*h}{g}}\\t=\sqrt{\frac{2*0.820m}{9.8\frac{m}{s^{2} } }}\\t=0.409s$

Now is the same time the piece travel horizontally

$L=t*V\\L=0.409s*8.7\frac{m}{s}\\L=3.55m$

blade piece travels HORIZONTALLY = (24.5)(0.397) = 9.73 m ANS

6 0

3 years ago

(4) 10 m/s

siniylev [52]

Answer:

Explanation:

6+4=10s

50+35=85

av speed=85/10=8.5m/s

4 0

2 years ago

Identify the reactions of the citric acid cycle that provide reducing power for the electron‑transport chain

svet-max [94.6K]

The reactions of the citric acid cycle that provide reducing power for the electron‑transport chain are as follows:

Conversion of isocitrate to α-ketoglutarate
Conversion of succinate to fumarate
Conversion of α-ketoglutarate to succinyl-coA

<h3>What is citric acid cycle?</h3>

Citric acid cycle also known as kreb cycle is a series of biochemical reactions that involves the synthesis of reduced electron carrier and ATP.

The following steps in the citric acid cycle involves the provision of reducing power for the electron‑transport chain:

Conversion of isocitrate to α-ketoglutarate: Isocitrate is converted to α-ketoglutarate as catalyzed by isocitrate dehydrogenase.
Conversion of α-ketoglutarate to succinyl-coA: α-ketoglutarate is converted to succinyl-coA as catalyzed by α-ketoglutarate dehydrogenase.

Learn more about citric acid cycle: brainly.com/question/11459709

7 0

2 years ago

These waves are needed for green plants to grow.

solong [7]

Answer:

visible waves are needed for green plants to grow.

Explanation:

During photosynthesis, chlorophyll absorbs energy from blue- and red-light waves, and reflects green-light waves, making the plant appear green.

8 0

1 year ago