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3 years ago

HELP PLEASE

Chemistry

1 answer:

MrMuchimi3 years ago

6 0

a) ionic

chlorine is present in top of group 17 and right of period 3 and

electronegativity(the tendency to gain electrons)

increases up the group and right the group.

so it has high tendency to form anion.

In the same way both Na and K are present up the group and left side and the tendency to lose electrons in both becomes high and they tend to form cation.

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The cost, C C, of producing x x Totally Cool Coolers is modeled by the equation C = 0.005 x 2 − 0.25 x + 12 C=0.005x2-0.25x+12 H

neonofarm [45]

Answer:

25 coolers are need to be produce and sell in order to minimize the cost.

Explanation:

$C = 0.005x^2-0.25x+12$ ..[1]

Differentiating the given expression with respect to dx.

$\frac{dC}{dx}=\frac{d(0.005x^2-0.25x+12)}{dx}$

$\frac{dC}{dx}=0.01x-0.25+0$

Putting , $\frac{dC}{dx}=0$

$0=0.01x-0.25+0$

$0.01x=0.25$

x = 25

Taking second derivative of expression [1]

$\frac{d^2C}{dx^2}=\frac{d(0.01x-0.25)}{dx}=0.01$

$\frac{d^2C}{dx^2}>0$ (minima)

25 coolers are need to be produce and sell in order to minimize the cost.

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3 years ago

If the bright lines in the spectrum of oxygen are matched by lines in the dark-line spectrum of the sun, what does that indicate

julsineya [31]

The correct answer is :
$The sun burns its fuel using oxygen.$

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4 years ago

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A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final

KATRIN_1 [288]

Answer : The initial temperature of the limestone is $1.05\times 10^{2}^oC$ .

Solution : Given,

Mass of limestone = 62.6 g

Mass of water = 75 g

Final temperature of limestone = $51.9^oC$

Final temperature of water = $51.9^oC$

Initial temperature of water = $23.1^oC$

The specific heat capacity of limestone = $0.921J/g^oC$

The specific heat capacity of water = $4.186J/g^oC$

The formula used :

q = m × c × ΔT

where,

q = heat required

m = mass of an element

c = heat capacity

ΔT = change in temperature

According to this, the energy as heat lost by the system is equal to the gained by the surroundings.

Now the above formula converted and we get

$q_{system}=-q_{surrounding}$

$m_{system}\times c_{system}\times (T_{final}-T_{initial})_{system}= -[m_{surrounding}\times c_{surrounding}\times (T_{final}-T_{initial})_{surrounding}]$

$m_{limestone}\times c_{limestone}\times (T_{final}-T_{initial})_{limestone}= -[m_{water}\times c_{water}\times (T_{final}-T_{initial})_{water}]$

Now put all the given values in this formula, we get

$62.6g\times 0.921J/g^{0}C \times (51.9^{0}C-T_{\text{ initial limestone}})= -[75g\times 4.186J/g^{0}C \times (51.9^{0}C-23.1^oC)]$

By rearranging the terms, we get the value of initial temperature of limestone.

$T_{\text{ initial limestone}}=104.926^{0}C=1.05\times 10^{2}^oC$

Therefore, the initial temperature of the limestone is $1.05\times 10^{2}^oC$ .

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Kitty [74]

Answer:

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V(O2) = 48.4 L

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T = 190 + 273 = 463 K

Ideal gas law:

pV = nRT

n = \frac{pV}{RT}n=

R = 0.08206 L×atm/mol×K

n(O2) = \frac{1.036 \times 48.4}{0.08206 \times 463}=1.319 \; mol=

0.08206×463

1.036×48.4

=1.319mol

According to the reaction:

n(H2S) = \frac{2}{3}

n(O2) = \frac{2}{3} \times 1.319 = 0.8798 \;mol

×1.319=0.8798mol

V = \frac{nRT}{p} \\ V(H_2S) = \frac{0.8798 \times 0.08206 \times 463}{1.036}=32.26 \;LV=

nRT

V(H

S)=

1.036

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Answer: 32.26 L

Explanation:

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Solnce55 [7]

Answer:

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Explanation:

The molecule is always polar because of two reasons:

all the bonds are polar due to the difference in electronegativity between carbon and hydrogen & carbon and chlorine.

AND IMPORTANTLY

The molecule is asymmetrical meaning that the dipoles cannot cancel each other out (like they do in methane or carbon dioxide for example) so the net effect is a polar molecule.

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4 years ago