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Delicious77 [7]
3 years ago
9

Does anyone know the answer?????​

Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

In chemistry, pH (/piːˈeɪtʃ/) (abbr. power of hydrogen or potential for hydrogen) is a scale used to specify how acidic or basic a water-based solution is. Acidic solutions have a lower pH, while basic solutions have a higher pH.

Explanation:

that should answer ur question

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How many molecules are in 88g of carbon dioxide?
Volgvan
No of moles= 88/44 =2
therefore no. of molecules =

therefore no.of molecules= 12.046*10^23
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An element has the mass number 12 and atomic number 6. The number of neutron in it is?
slamgirl [31]

Answer:

12-6=6

the answer is A)6

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An ideal gas is a gas. <br> Perfect<br> Theoretical<br> Real
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Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
3 years ago
there are 28L of soup in a pot. Marshall serves 400mL in each bowl. If he fills 16 bowls how much soup is left in the pot? in li
Ne4ueva [31]
Total in pot=28 L
400 mL in each bowl
16 bowls filled
1000mL=1L
16 bowls(400mL/1 bowl)=6400mL
6400mL(1L/1000mL)=6.4L
28L-6.4L=21.6 L
5 0
4 years ago
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