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Vilka [71]
3 years ago
10

A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul

d the new volume of the balloon be
Chemistry
1 answer:
WITCHER [35]3 years ago
5 0
Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
 
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

                                        P1*v1/T1 =  P2*v2/T2
As, the temperature is constant;
 So,
                                               v1/T1 = v2/T2
                                              417/278 = v2/231
                                                  v2= 346.5 cm³                                           
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Which statements about the operation of an automated micropipettor are true? The volume dial has already been set, do not alter
yanalaym [24]

Answer:

The correct statement is that the point of initial resistance is the level of depression that will fill the pipette with the desired volume of solution.

Explanation:

The pipette can be otherwise stored vertically or horizontally, this has nothing to do with the operation, and before the operation, the dial needs to be set. Also, the plastic pipette tip should not be ejected at all, thus, no new disposable plastic tip is required for each sample.

The correct statement is that the point of initial resistance is the level of depression that will fill the pipette with the desired volume of solution.

4 0
3 years ago
Which of the following solids would not decompose on heating​
Gekata [30.6K]

Answer:

Anhydrous sodium carbonate is stable to heat and does not decompose even when it is heated to redness. This is because sodium carbonate salt on heating with acids react to release carbon dioxide.

5 0
3 years ago
Sulfur oxide is a main source of acid deposition. <br> a. True <br> b. False
ICE Princess25 [194]
True

The main chemicals in air pollution that create acid rain are sulfur dioxide (SO2) and nitrogen (NOx).
3 0
3 years ago
0.2640 g of sodium oxalate is dissolved in a flask and requires 30.74 mL of potassium
Free_Kalibri [48]

Moles of potassium permanganate = 0.0008

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Reaction

5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) +  10CO2(g) + 8H2O(1)

The end point ⇒titrant and analyte moles equal

titrant : potassium  permanganate-KMnO4

analyte : sodium oxalate - Na2C2O4

so moles of KMnO4 = moles of Na2C2O4

moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.264}{134 g/mol}\\\\mol=0.002

From equation, mol ratio  Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

\tt \dfrac{2}{5}\times 0.002=0.0008

6 0
3 years ago
A teacher wrote the following part of a balanced chemical equation: Cu+2AgNO 3 To show the conservation of matter in the chemica
Llana [10]
2, because there are 2 silver atoms on the left
7 0
3 years ago
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