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3 years ago

The chemical bond between which two atoms is most polar? (1) C–N (3) S–Cl (2) H–H (4) Si–O

Chemistry

2 answers:

jeka943 years ago

7 0

(4) Si-O is the most polar, since their differences in electronegativity is the highest.

Vilka [71]3 years ago

5 0

Correct Answer: option 4: Si-O

Reason:
The bond polarity depends on the electronegativity difference between constituent atoms. Greater the electronegativity difference, polar is the bond. In present case, electronegativity of Si and O is 1.9 and 3.44 respectively. Hence, electronegativity difference is 1.54, which is greater as compared to other bonds on present interest. Hence, Si-O bond is considered to be more polar.

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A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and

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Answer:

1. $Rate =k [NO]^{2}[Cl_{2}]$

2. $k= 0.42 \frac{L^{2}}{mol^{2}*s}$

Explanation:

$Rate =k [NO]^{m}[Cl_{2}]^{n}$

$Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2$

$Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1$

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$Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12} = 0.42 \frac{L^{2}}{mol^{2}*s}$

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3 years ago

Which element will chemically combine with fluorine to combine salt?

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Answer:

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Explanation:

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3 years ago

Chlorine has two naturally stable isotopes: 35Cl (34.968853 amu) and 37Cl (36.965903 amu). The natural abundance of each isotope

allochka39001 [22]

Answer:

35Cl ⇒ 34.968853 amu has an abundance of 30.05%

Explanation:

The molar mass of chlorine, (which is the average of all its naturally stable isotope masses), is 36.36575 amu.

There are 2 naturally stable isotopes, this means together they have an abundance of 100%

The isotopes are:

35Cl ⇒ 34.968853 amu has an abundance of X %

37Cl ⇒ 36.965903 amu has an abundance of Y %

X + Y = 100% OR X = 100% - Y

36.36575 = 34.968853X + 36.965903Y

36.36575 = 34.968853(1-Y) + 36.936.96590365903Y

36.36575 = 34.968853 -34.968853Y + 36.965903Y

1.396897 = 1.99705Y

Y = 0.699 = 69.95%

X = 100-69.9 = 30.05%

To control, we can plug in the following equation:

34.968853 * 0.3005 + 36.965903 * 0.6995 = 36.3658

This means

37Cl ⇒ 36.965903 amu has an abundance of 69.95 %

35Cl ⇒ 34.968853 amu has an abundance of 30.05%

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4 years ago

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