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3 years ago

The chemical bond between which two atoms is most polar? (1) C–N (3) S–Cl (2) H–H (4) Si–O

Chemistry

2 answers:

jeka943 years ago

7 0

(4) Si-O is the most polar, since their differences in electronegativity is the highest.

Vilka [71]3 years ago

5 0

Correct Answer: option 4: Si-O

Reason:
The bond polarity depends on the electronegativity difference between constituent atoms. Greater the electronegativity difference, polar is the bond. In present case, electronegativity of Si and O is 1.9 and 3.44 respectively. Hence, electronegativity difference is 1.54, which is greater as compared to other bonds on present interest. Hence, Si-O bond is considered to be more polar.

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Give a brief description of what is needed to properly formate a table and chart

Lelechka [254]

Answer:Name your table. Write a title at the top of your paper. ...

Figure out how many columns and rows you need.

Draw the table. Using a ruler, draw a large box. ...

Label all your columns. ...

Record the data from your experiment or research in the appropriate columns. ...

Check your table.

Explanation:

3 0

3 years ago

The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine

Viefleur [7K]

Answer:

16.2 J

Explanation:

Step 1: Given data

Specific heat of liquid bromine (c): 0.226 J/g.K

Volume of bromine (V): 10.0 mL

Initial temperature: 25.00 °C

Final temperature: 27.30 °C

Density of bromine (ρ): 3.12 g/mL

Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

ρ = m/V

m = ρ × V

m = 3.12 g/mL × 10.0 mL

m = 31.2 g

Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

7 0

3 years ago

In a simplified model of a hydrogen atom, the electron moves around the proton nucleus in a circular orbit of radius 0.53 × x10−

sergiy2304 [10]

the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".

the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration

the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given

<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given

3 0

4 years ago

What is the boiling point elevation constant, Kb, of diethyl ether if 38.2 g of the nonelectrolyte benzophenone, C6H5COC6H5, dis

kakasveta [241]

Answer: the boiling point elevation constant is $1.73^0C/m$

Explanation:

Elevation in boiling point is given by:

$\Delta T_b=i\times K_b\times m$

$\Delta T_b=T_b-T_b^0=$ = Elevation in boling point

i= vant hoff factor = 1 (for non electrolyte)

$K_b$ =boiling point constant = ?

m= molality

$\Delta T_b=i\times K_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (diethylether)= 330 g = 0.33 kg

Molar mass of solute (benzophenone)= 182 g/mol

Mass of solute (benzophenone) = 38.2 g

$(35.7-34.6)^0C=1\times K_b\times \frac{38.2g}{182g/mol\times 0.33kg}$

$K_b=1.73^0C/m$

Thus the boiling point elevation constant is $1.73^0C/m$

3 0

3 years ago

What is the frequency of 3.98 x 10^-77

LekaFEV [45]

Answer:

What is the frequency of a 6.9 x 10-13 m wave? 3.00 x 108 = 6.9x10-13 mly). GAMMA. V = 4.35 x 10 20 5-11. 3. What is the wavelength of a 2.99 Hz wave?

Missing: 3.98 ‎77

Explanation:

5 0

3 years ago