1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Soloha48 [4]
3 years ago
10

A student wanted to investigate whether or not the temperature of the water would affect the solubility of sugar. She had three

glasses of water each with 200 mL of water in them. One was at 10 degrees Celsius the 2nd at 25 degrees Celsius and the third was at 40 degrees celsius she found that the warmer the water dissolve more sugar. what are the independent and dependent variables
Physics
1 answer:
erastova [34]3 years ago
5 0

ind variable ... temp

dep variable .... amount of sugar dissolved

You might be interested in
Not understanding this, please help out
allsm [11]

Answer:

greater than

Explanation:

the answer is greater than

3 0
3 years ago
A block with a mass of 0.600 kg is connected to a spring, displaced in the positive direction a distance of 50.0 cm from equilib
tankabanditka [31]

Answer:

Explanation:

The amplitude of the oscillation under SHM will be .5 m and the equation of

SHM can be written as follows

x = .5 sin(ωt + π/2) , here the initial phase is π/2 because when t = 0 , x = A ( amplitude) , ω is angular frequency.

x = .5 cosωt

given , when t = .2 s , x = .35 m

.35 = .5 cos ωt

ωt = .79

ω = .79 / .20

= 3.95 rad /s

period of oscillation

T = 2π / ω

= 2 x 3.14 / 3.95

= 1.6 s

b )

ω = \sqrt{\frac{k}{m} }

ω² = k / m

k = ω² x m

= 3.95² x .6

= 9.36 N/s

c )

v = ω\sqrt{(a^2-x^2)}

At t = .2 , x = .35

v = 3.95 \sqrt{.5^2-.35^2}

= 3.95 x .357

= 1.41 m/ s

d )

Acceleration at x

a = ω² x

= 3.95 x .35

= 1.3825 m s⁻²

7 0
3 years ago
The common version of Newton’s second law of motion, EF= ma, is actually a special case that is true only when an objects _____
vladimir2022 [97]

Answer:

A

Explanation:

only is true when the objects mass is constant

6 0
3 years ago
Read 2 more answers
A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
marishachu [46]

Answer:

The impact occured at a distance of 2478.585 meters from the person.

Explanation:

(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:

<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>

Sound is a manifestation of mechanical waves, which needs a medium to propagate themselves. Depending on the material, sound will take more or less time to travel a given distance. From statement, we know this time difference between air and concrete (\Delta t), in seconds:

\Delta t = t_{A}-t_{C} (1)

Where:

t_{C} - Time spent by the sound in concrete, in seconds.

t_{A} - Time spent by the sound in the air, in seconds.

By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:

\Delta t = \frac{x}{v_{A}}-\frac{x}{v_{C}}

\Delta t = x\cdot \left(\frac{1}{v_{A}}-\frac{1}{v_{C}}  \right)

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  } (2)

Where:

v_{C} - Speed of the sound in concrete, in meters per second.

v_{A} - Speed of the sound in the air, in meters per second.

x - Distance traveled by the sound, in meters.

If we know that \Delta t = 6.4\,s, v_{C} = 3000\,\frac{m}{s} and v_{A} = 343\,\frac{m}{s}, then the distance travelled by the sound is:

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  }

x = 2478.585\,m

The impact occured at a distance of 2478.585 meters from the person.

7 0
3 years ago
Why does a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude
inna [77]

Answer:

According to your question although I think an object undergoing uniform circular motion is moving with a constant speed. Nevertheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards,therefore a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude.

3 0
4 years ago
Other questions:
  • You are riding on a school bus and suddenly get thrown forward. What did the bus just do?
    15·2 answers
  • The assembly consists of two red brass C83400 copper rods AB and CD of diameter 30 mm, a stainless 304 steel alloy rod EF of dia
    7·1 answer
  • A particle, whose acceleration is constant, is moving in the negative x direction at a speed of 4.91 m/s, and 12.9 s later the p
    14·1 answer
  • Explain how fusion and fission are similar to and different from each other. Thanks.
    13·2 answers
  • Is there any induced current in the pickup coil when the polarity of the bar magnet is flipped?
    15·1 answer
  • CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY! I ALSO NEED SOMEONE TO HELP ME WITH MORE QUES
    10·2 answers
  • Consider a gymnast performing the "iron cross" on the rings. What magnitude of moment must be produced at each shoulder joint to
    7·1 answer
  • Pierre is a 375 kg great white with an average speed of 3 m/s. When Pierre spots a seal, he increases his velocity to 7 m/s. Aft
    8·1 answer
  • A cylindrical water tank has a height of 20cm and a radius of 14cm. If it is filled to 2/5 of its capacity, calculate.
    8·2 answers
  • A 1,000 kg ball traveling at 5 m/s would have kinetic energy. A 10 kg ball traveling at 5 m/s would have kinetic energy. A 100 k
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!