Explanation:
Using the formula;
2x = vt
x is the distance up from the ocean floor the submarine is
v is the speed of sound in water
t is the time
Given
t = 2.3s
v = 1490m/s
Required
how high (approx) up from the ocean floor is the submarine x
From the formula;
x = vt/2
x = 1490(2.3)/2
x = 745(2.3)
x = 1,713.5m
Hence the submarine is 1713.5m high up from the ocean floor
The maximum energy that can be transferred by the electrical generator is 2.7×10¹³ Joules.
We can use the equation of electric power and electric energy.
Electric Power: This can be defined as the ratio of the electric energy to the time of electrical equipment.
⇒ Formula
- P = E/t............... Equation 1
⇒Where:
- P = Maximum electric power
- E = Maximum electric Energy
- t = time.
make E the subject of the equation
- E = Pt................. Equation 2
From the question,
⇒ Given:
- P = 1.5×10⁹ W
- t = 5 hours = (5×60×60) seconds = 18000 seconds = 1.8×10⁴ s
⇒ Substitute these values into equation 2
- E = (1.5×10⁹)(1.8×10⁴)
- E = 2.7×10¹³ Joules.
Hence, the maximum energy that can be transferred by the electrical generator is 2.7×10¹³ Joules.
Learn more about Electric energy here: brainly.com/question/21222010
Answer:
![f_2 = 18.5 kHz](https://tex.z-dn.net/?f=f_2%20%3D%2018.5%20kHz)
Explanation:
As the two whistle are played simultaneously
we know that we will hear beats in that case
so we can say
![f_{beat} = f_1 - f_2](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%20f_1%20-%20f_2)
so here we will have
![f_1 = 23.5 kHz](https://tex.z-dn.net/?f=f_1%20%3D%2023.5%20kHz)
also we know that the shrill that we feel when both whistle are sounded
![f_{beat} = 5000 Hz](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%205000%20Hz)
so the unknown frequency is given as
![f_{beat} = 23.5 kHz - f_2](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%2023.5%20kHz%20-%20f_2)
![5000 = 23.5 - f_2](https://tex.z-dn.net/?f=5000%20%3D%2023.5%20-%20f_2)
![f_2 = 18.5 kHz](https://tex.z-dn.net/?f=f_2%20%3D%2018.5%20kHz)
The gravitional potential energy, relative to the bottom of the giant drop, in joules, is (9800) times (the height of the drop in meters).
That's the PE of the empty car only, not counting any hapless screaming souls who may be trapped in it at that moment.
The effort applied : 200 N
<h3>Further explanation</h3>
Equilibrium rotation
![\large {\boxed {\bold {\sum \tau = 0}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7B%5Csum%20%5Ctau%20%3D%200%7D%7D)
F₁.d₁-F₂.d₂=0
F₁.d₁=F₂.d₂
F₁=500 N
d₁=0.5 m
d₂=1.75-0.5=1.25 m
![\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N](https://tex.z-dn.net/?f=%5Ctt%20500%5Ctimes%200.5%3DF_2%5Ctimes%201.25%5C%5C%5C%5CF_2%3D%5Cdfrac%7B500%5Ctimes%200.5%7D%7B1.25%7D%3D200~N)