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castortr0y [4]
4 years ago
5

Why does a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude

Physics
1 answer:
inna [77]4 years ago
3 0

Answer:

According to your question although I think an object undergoing uniform circular motion is moving with a constant speed. Nevertheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards,therefore a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude.

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g The electric field in a sinusoidal wave changes as E =125 N>C2cos 311.2 * 1011 rad>s2t +14.2 * 102 rad>m2x] (a) In wh
Elan Coil [88]

Answer:

a) the propagation direction is x, b)   E₀ = 125 N / C² , c) B = 41.67 10⁻⁸ T ,

d)  f = 4.95 10¹¹ Hz, e)  λ = 4.42 10⁻³ m, f) the speed of light ,

Explanation:

The equation they give for the sine wave is

      E = 125 cos (14.2 10² x - 311.2 10¹¹ t)

This expression must have the general shape of a traveling wave

      E = Eo cos (kx - wt + Ф)

we can equal each term between the two equations

a) the propagation direction is x, since it is the term that accompanies the vector k

b) the amplitude is the coefficient before the cosine function

          E₀ = 125 N / C²

c) to find the amplitude of the magnetic field we use that the two fields are in phase

          C = E / B

          B = E / c

          B = 125/3 10⁸

          B = 41.67 10⁻⁸ T

d) the angular velocity is

          w = 311.2 10¹¹ rad / s

angular velocity and frequencies are related

          w = 2π f

           f = w / 2π

           f = 311.2 10¹¹ / 2π

           f = 4.95 10¹¹ Hz

e) the wavelength is obtained from the wave number

          k = 2π /λ

          k = 14.2 10² rad / m

          λ = 2π / k

          λ = 2π / 14.2 10²

          λ = 4.42 10⁻³ m

f) the speed of an electromagnetic wave is the speed of light

g) what is a transverse wave

4 0
3 years ago
Why do people walks bare feel pain
matrenka [14]

Answer:

As we age the fat pad underneath the bones at the front of our feet (metatarsal heads) and under the heel bone become thinner or “migrate” away from where they are most needed

8 0
3 years ago
What kinds of bonds can happen between the elements of a compound
Anit [1.1K]
What kinds of bonds can happen between the elements of a compound?

<span>Covalent and Ionic</span>

4 0
3 years ago
Help me on question 3 pls I’m giving out brainlest
emmasim [6.3K]

Answer:

Its 150?

Explanation:

5³= 5×5×5

I hope its help :)

3 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x'(t) is its velocity, and x''
Lady_Fox [76]

Answer:

We know that the acceleration of the particle is defined as

a(t)=\frac{dv}{dt}

Since it is given that

v(t)=\frac{5}{\sqrt{t}}\\\\\therefore a(t)=\frac{d(\frac{5}{\sqrt{t}})}{dt}\\\\a(t)=5\times \frac{dt^{-\frac{1}{2}}}{dt}\\\\=\frac{-5}{2}t^{\frac{-1}{2}-1}\\\\\therefore a(t)=x''(t)=\frac{-2.5}{t^{\frac{3}{2}}}

Now by definition of velocity we have

v(t)=\frac{dx(t)}{dt}\\\\\Rightarrow dx(t)=v(t)dt

Integrating on both sides we get

v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int v(t)dt

Applying values we get

v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int \frac{5}{t^{\frac{1}{2}}}dt\\\\\therefore x(t)=\frac{5}{0.5}\int t^{-0.5}dt\\\\x(t)=10\sqrt{t}+c

To find the constant we note that at t=1 the particle is at x=12 Thus applying values in the above equation we get

c=12-10\\\therefore c=2\\\\x(t)=10\sqrt{t}+2

6 0
3 years ago
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