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Anettt [7]
3 years ago
6

Hydrogen fluoride gas (HF) and sodium hydroxide (NaOH) react in a test tube. They form water and sodium fluoride (NaF). Which ty

pe of reaction occurred in the test tube?
single–replacement reaction
decomposition reaction
acid–base reaction
synthesis reaction
Physics
1 answer:
solmaris [256]3 years ago
8 0
The type of reaction that occurred in the test tube is ACID BASE REACTION.
Acid base reaction is a type of chemical reaction in which an acid and a base react together to form salt and water molecules. It is also known as neutralization reaction. For the question given above, the applicable chemical reaction is as follows:
HF + NaOH = NaF + H2O
 From this chemical reaction, it can be seen that, hydrogen fluoride, which is a weak acid react with sodium hydroxide which is a strong base to produce sodium fluoride, which is a salt and a molecule of water.
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Which of the following is the visible part of the spectrum of light?
mestny [16]
The visible spectrum<span> is portion of the </span>electromagnetic spectrum<span> that is </span>visible <span>to the </span><span>human eye.
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6 0
2 years ago
Read 2 more answers
A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.40 kg box that is sitting on the horizontal,
Fynjy0 [20]

Answer:v=7.24 m/s

Explanation:

Given

F(x)=18-0.530 x

mass m=8.40 kg

box is at rest at x=0

Distance traveled=16 m

mv\frac{\mathrm{d} v}{\mathrm{d} x}=F=\left ( 18-0530x\right )dx

\int_{0}^{v}vdv=\int_{0}^{16}\left ( 18-0.530x\right )dx

\frac{mv^2}{2}=\left ( 18x-0530\frac{x^2}{2}\right )_0^{16}

v^2=\frac{288-67.841\times 2}{8.40}

v=7.24 m/s

6 0
2 years ago
Find the gravitational potential energy of a light that has a mass of 13.0 kg and is 4.8 m above the ground
Lynna [10]

Answer:

611.52 <---- Is your answer

Explanation:

If you need explanation mark me as brain list

8 0
2 years ago
If a team pulls with a combined force of 4 newtons on an airplace with a mass of 36 kilograms,what is the acceleration of the ai
MatroZZZ [7]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                    \boxed{F=ma}

                                                 <u>Δ   Being   Δ</u>

                                                F = Force = 4 N

                                              m = mass = 36 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula:

\boxed{4\ N = 36\ kg * \textbf{a}}

⇒ Clear acceleration and resolve it:

\boxed{\textbf{a}=0,111\ m/s^{2}}}

Result:

The aceleration is of <u>0,111 meters per second squared (m/s²)</u>

Good Luck!!

5 0
2 years ago
A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?
Alisiya [41]

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

7 0
3 years ago
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