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Luda [366]
2 years ago
12

A bicycile traves with an average velocty 15km/h north for 20min what is his displasment​

Physics
1 answer:
Mila [183]2 years ago
6 0

Answer:

5000 m equivalent to 5 Km

Explanation:

Average velocity =\frac{Displacement}{Time}

so, Displacement =Average velocity × time

We should convert Km/h to m/s so Km/h ⇒ \frac{1000}{60*60} m/s, also convert time to second so, 20min ⇒(20* 60)seconds

Displacement = (15 ×\frac{1000}{60*60}) × (20×60) =5000m OR 5Km

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A proton in a high-energy accelerator is given a kinetic energy of 50.0 GeV. Determine (a) the momentum and (b) the speed of the
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(a) The momentum of the proton is determined as 5.17 x 10⁻¹⁸ kgm/s.

(b) The speed of the proton is determined as  3.1 x 10⁹ m/s.

<h3>Momentum of the proton</h3>

The momentum of the proton is calculated as follows;

K.E = ¹/₂mv²

where;

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v² = 2K.E/m

v² = (2 x 50 x 10⁹ x 1.602 x 10⁻¹⁹ J)/(1.67 x 10⁻²⁷)

v² = 9.6 x 10¹⁸

v = 3.1 x 10⁹ m/s

<h3>Momentum of the proton</h3>

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Learn more about momentum here: brainly.com/question/7538238

#SPJ4

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Answer:

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Explanation:

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