Answer:

Explanation:
You calculate the energy required to break all the bonds in the reactants.
Then you subtract the energy needed to break all the bonds in the products.
CH₃CH₂OH + 3O₂ ⟶ 2CO₂ + 3H₂O
Bonds: 5C-H 1C-C 1C-O 1O-H 3O=O 4C=O 6O-H
D/kJ·mol⁻¹: 413 347 358 467 495 799 467

Answer: __3__Na2CO3 + __2__Ag3P → __2__Na3P + __3__Ag2CO3
Explanation:
In balancing equations you need to make sure the number of atoms before the reaction should be equal to the number of atoms after the reaction.
Before the reaction: We had 6Na, 9CO, 6Ag and 2p
After the reaction: We have 6Na, 9CO, 6Ag and 2p
And now we are sure that atoms before the reaction are equal to atoms after the reaction
Answer:
100mL of 0.10M HNO2 and 0.10M NaNO2
Explanation:
because solution has the greatest buffering capacity when the concentration of the weak acid is = at the concentration of its conjugate base.