Answer:
The correct option is FALSE
Explanation:
Mole ratio is the ratio of the number of moles of two compounds in a balanced chemical reaction. Number of moles of a compound in a chemical reaction is the number written before the compound.
For example, the mole ratio of Iron (Fe) and water (H₂O) in the equation below is 3:4
3Fe + 4H₂O ⇒ Fe₃O₄ + 4H₂
Thus, mole ratio does not compare subscripts of compounds.
Answer:
3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.
Explanation:

Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
= Initial temperature of the substance
= Final temperature of the substance
We have mass of isopropyl alcohol = m = 25.0 g
Specific heat of isopropyl alcohol = c = 2.604 J/g°C
Initial temperature of the isopropyl alcohol = 
Final temperature of the isopropyl alcohol = 
Heat absorbed by the isopropyl alcohol to boil:

3984.12 J joules of heat are required to heat 25.0 g of isopropyl alcohol to its boiling point.
<h3>The temperature is 15.58 kelvin </h3>
<em><u>Solution:</u></em>
<em><u>Ideal gas equation is given as:</u></em>

Where,
P = pressure
V = volume
n = amount of substance
R = ideal gas constant
T = temperature
From given,
V = 120 liters
n = 5 moles

P = 5.4 kPa
T = ?
Therefore,

Thus the temperature is 15.58 kelvin
Answer:
See explanation
Explanation:
When we look at SO3 we will notice that the compound is trigonal planar and it is symmetric. This means that it has equal charge distribution hence its dipoles cancel out resulting in a zero net dipole moment.
However, COH2 is also trigonal planar but is non-symmetric. Hence, its dipole moments do not cancel out, hence the molecule has a resultant dipole moment and is a polar molecule
Answer: 35.4 grams
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,
Molality = 2.65
n= moles of solute =?
= volume of solution in ml = 445 ml
Putting in the values we get:


Mass of solute in g=
Thus 35.4 grams of
is needed to prepare 445 ml of a 2.65 m solution of
.