On a roller coaster, the greatest potential energy is at the highest point of the roller coaster
Answer
given,
resistance = 0.05 Ω
internal resistance of battery = 0.01 Ω
electromotive force = 12 V
a) ohm's law
V = IR
and volage
now,

inserting the values
I = 200 A
b) Voltage
V = I R
V = 200 x 0.05
V = 10 V
c) Power
P = I V
P = 200 x 10 = 2000 W
d) total resistance = 0.05 + 0.09 = 0.14 Ω
I = 80 A
V = 80 x 0.05 = 4 V
P = 4 x 80 = 320 W
: the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation a string on the end of which a stone is whirled about exerts centripetal<span> force on the stone — compare centrifugal force.</span>
-- In order to achieve constant verlocity, the net force on the mass must be zero. So if there ARE any forces acting on it, they must be balanced.
-- There is already a force on the mass that can't be eliminated . . . the force of gravity.
-- That force due to gravity is (mass x gravity) = (25 kg)(9.8 m/s²) = <em><u>245N</u></em> in the <u><em>downward</em></u> direction.
-- In order to 'balance' the forces and make them add up to zero, we have to provide another force of <em>245N</em>, all in the <em>upward</em> direction.
-- Then the forces on the object will be balanced, the NET force on it will be zero, and whichever way you start it moving, it will continue to move at a cornstant verlocity.
Answer:
(a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.
Explanation:
Given that,
Time = 1.95 s
Distance = 23.5 m
(a). We need to calculate the velocity
Using equation of motion

Put the value into the formula



(b). We need to calculate the total distance the object travels during the fall
Using equation of motion

Put the value in the equation



The total time is


We need to calculate the distance
Using equation of motion

Put the value into the formula


Hence, (a). The velocity of the object is -2.496 m/s.
(b). The total distance of the object travels during the fall is 23.80 m.