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3 years ago

13

Therefore an answer in U.S. customary units, such as miles per hour would not be accepted as correct. A car traveling with const

ant speed travels 150 kmkm in 7200 ss. What is the speed of the car

2 answers:

allochka39001 [22]3 years ago

6 0

Answer:

The speed of the car is 20.84 m/s.

Explanation:

Given that,

The distance covered by the car, d = 150 km

Time, t = 7200 s

We need to find the speed of the car. We know that the speed of an object is given by total distance divided by total time taken. Mathematically,

$v=\dfrac{d}{t}\\\\v=\dfrac{150\times 10^3\ m}{7200\ s}\\\\v=20.84\ m/s$

So, the speed of the car is 20.84 m/s.

pychu [463]3 years ago

3 0

Answer:

calculate it. its not cheating, its like flash cards but better, besides its made for that reason.;)

Explanation:

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Helppppp!!<br> can a current run through a metal conductor can create a magnetic field

sineoko [7]

Answer:

yesssssssssssssssssss

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3 years ago

Conversion fraction 1$=4q, how many are in 20$

Tom [10]

Answer:

$\boxed{\sf 20 \$ = 80q}$

Given:

1$ = 4q

To Find:

How many quarters are in 20$

Explanation:

To find out how many quarters are in 20$ we need to multiple 4 × 20.

$\sf 1\$ = 4q$

$\sf 20\$ = 4 \times 20q$

$\sf = 80q$

8 0

3 years ago

Read 2 more answers

Water is being boiled in an open kettle that has a 0.52-cm-thick circular aluminum bottom with a radius of 12.0 cm. If the water

tangare [24]

Answer:

$T_b=107.3784\ ^{\circ}C$

Explanation:

Given:

thickness of the base of the kettle, $dx=0.52\ cm=5.2\times 10^{-3}\ m$

radius of the base of the kettle, $r=0.12\ m$

temperature of the top surface of the kettle base, $T_t=100^{\circ}C$

rate of heat transfer through the kettle to boil water, $\dot Q=0.409\ kg.min^{-1}$

We have the latent heat vaporization of water, $L=2260\times 10^3\ J.kg^{-1}$

and thermal conductivity of aluminium, $k=240\ W.m^{-1}.K^{-1}$

<u>So, the heat rate:</u>

$\dot Q=\frac{0.409\times 2260000}{60}$

$\dot Q=15405.67\ W$

<u>From the Fourier's law of conduction we have:</u>

$\dot Q=k.A.\frac{dT}{dx}$

$\dot Q=k\times \pi.r^2\times \frac{T_b-T_t}{5.2\times 10^{-3}}$

where:

$A=$ area of the surface through which conduction occurs

$T_b=$ temperature of the bottom surface

$15405.67=240\times \pi\times 0.12^2\times \frac{T_b-100}{5.2\times 10^{-3}}$

$T_b=107.3784\ ^{\circ}C$ is the temperature of the bottom of the base surface of the kettle.

6 0

3 years ago

What is the safety rules?

Black_prince [1.1K]

Answer:

Quick question do you mean what are some safety rules

Explanation:

Crosswalk, Stop sign,

5 0

3 years ago

Read 2 more answers

skater spins over a point at a speed of 3.0 rotations per second then the momentum of inertia is 0.60 kg.M2, what is its angular

laiz [17]

Answer:

$L=11.3\ kg-m^2/s$

Explanation:

Given that,

Angular speed of a skater, $\omega=3\ rot/s=18.84\ rad/s$

The moment of inertia of the skater, I = 0.6 kg-m²

We need to find the angular momentum of the skater. The formula for the angular momentum of the skater is given by :

$L=I\omega$

Substitute all the values,

$L=0.6\times 18.84\\\\L=11.3\ kg-m^2/s$

So, its angular momentum is equal to $11.3\ kg-m^2/s$ .

8 0

3 years ago