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ikadub [295]
3 years ago
13

Therefore an answer in U.S. customary units, such as miles per hour would not be accepted as correct. A car traveling with const

ant speed travels 150 kmkm in 7200 ss. What is the speed of the car
Physics
2 answers:
allochka39001 [22]3 years ago
6 0

Answer:

The speed of the car is 20.84 m/s.

Explanation:

Given that,

The distance covered by the car, d = 150 km

Time, t = 7200 s

We need to find the speed of the car. We know that the speed of an object is given by total distance divided by total time taken. Mathematically,

v=\dfrac{d}{t}\\\\v=\dfrac{150\times 10^3\ m}{7200\ s}\\\\v=20.84\ m/s

So, the speed of the car is 20.84 m/s.

pychu [463]3 years ago
3 0

Answer:

calculate it. its not cheating, its like flash cards but better, besides its made for that reason.;)

Explanation:

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You walk six blocks east along 12th Street, then three blocks west, then one block east, then six blocks east, then seven blocks
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The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of t
zysi [14]

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3 0
2 years ago
An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b
lys-0071 [83]

Answer:

a)Distance traveled during the first second = 4.905 m.

b)Final velocity at which the object hits the ground = 38.36 m/s

c)Distance traveled during the last second of motion before hitting the ground = 33.45 m

Explanation:

a) We have equation of motion

             S = ut + 0.5at²

     Here u = 0, and a = g

              S = 0.5gt²

    Distance traveled during the first second ( t =1 )

              S = 0.5 x 9.81 x 1² = 4.905 m

   Distance traveled during the first second = 4.905 m.

b)  We have equation of motion

            v² = u² + 2as

      Here u = 0, s= 75 m and a = g

           v² = 0² + 2 x g x 75 = 150 x 9.81

           v = 38.36 m/s

      Final velocity at which the object hits the ground = 38.36 m/s

c) We have S = 0.5gt²

                   75 = 0.5 x 9.81 x t²

                    t = 3.91 s

   We need to find distance traveled last second

   That is

          S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m

   Distance traveled during the last second of motion before hitting the ground = 33.45 m

       

3 0
3 years ago
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