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ikadub [295]
3 years ago
13

Therefore an answer in U.S. customary units, such as miles per hour would not be accepted as correct. A car traveling with const

ant speed travels 150 kmkm in 7200 ss. What is the speed of the car
Physics
2 answers:
allochka39001 [22]3 years ago
6 0

Answer:

The speed of the car is 20.84 m/s.

Explanation:

Given that,

The distance covered by the car, d = 150 km

Time, t = 7200 s

We need to find the speed of the car. We know that the speed of an object is given by total distance divided by total time taken. Mathematically,

v=\dfrac{d}{t}\\\\v=\dfrac{150\times 10^3\ m}{7200\ s}\\\\v=20.84\ m/s

So, the speed of the car is 20.84 m/s.

pychu [463]3 years ago
3 0

Answer:

calculate it. its not cheating, its like flash cards but better, besides its made for that reason.;)

Explanation:

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the rate of work done or doing work is usually measured by the power of a machine .

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3 years ago
The image below represents molecules in which state of matter? *
Aleks04 [339]

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3 0
3 years ago
A spring of force constant 1500 Nm-l is acted
olchik [2.2K]

Answer:

1.876 J

Explanation:

First, let’s calculate the compression of the spring from the Hooke’s law:

F=kx,

here, F=75 N is the force acted on the spring, k=1500 N⁄m is the force constant of the spring, x is the compression of the spring.

Then, we get:

x=F/k=(75 N)/(1500 N/m)=0.05 m.

Finally, we can find the potential energy stored in the spring:

PE=1/2 kx^2=1/2∙1500 N/m∙(0.05 m)^2=1.875 J.

correct my answer if it's wrong ^^

7 0
3 years ago
6. A 73-kg woman stands on a scale in an elevator. The
olga nikolaevna [1]

Answer:

b

Explanation:

n = m(g +a)

n= normal force (N)

m=mass (kg)

g=acceleration of gravity

a= acceleration of elevator

rearrange:

a= n/m - g

a= (810 N/73 kg) - 9.8 m/s ^2

a= 1.3 m/s ^2 up

and the acceleration is upwards bc her weight is less than the scale reading

3 0
3 years ago
If 2050 J of heat are added to a 150 g object its temperature increases by 15°C.
Darina [25.2K]

When an object gets heated by a temperature ΔT energy needed, E = mcΔT

Here energy is given E = 2050 J

Mass of object = 150 g

Change in temperature ΔT  = 15 ^0C = 15 K

a) Heat capacity of an object equal to the ratio of the heat added to (or removed from) an object to the resulting temperature change.

  So heat capacity = E/ΔT = 2050/15 = 136.67 J/K

b) We have E = mcΔT

                    c = \frac{2050}{150*10^{-3}*15}  = 911.11 J/kgK

 So object's specific heat = 911.11 J/kgK

5 0
3 years ago
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