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notsponge [240]
3 years ago
10

A 6 V battery is connected to a 24 ohm resistor to create a circuit. The 6 V battery is then replaced with a 12 V battery. How d

oes the current change in the circuit when the 12 V battery is used instead of the 6 V battery? *
3 points
The current is reduced by one-fourth.
The current is reduced by one-half.
The current is doubled.
The current is tripled.

Which of the following actions can produce an electric current in a loop of wire? *
2 points
spinning the wire near a battery
placing a resistor at the end of the wire
heating a switch and placing it on the wire
moving a magnet up and down near the wire

A student began an investigation by wrapping several coils of insulated wire around a steel nail. As shown in the diagram, when the ends of the wire were connected to a battery, the student was able to pick up several steel paperclips with the end of the steel nail. Which of the following claims is best supported by the student’s investigation? *
2 points
Captionless Image
An electric current in the wire produces a magnetic field.
An electric current in the wire produces a potential difference.
A magnetic field can produce an electric current in the wire.
A magnetic field can produce an electric current in steel paper clips

A student made the graph below to show how the amount of electrical force between two charged particles depend son another variable. The student’s graph is missing a label for the x-axis. What should the student label the x-axis? *
2 points
Captionless Image
Volume of Particles (m^3)
Mass of One Particle (kg)
Charge of One Particle (C)
Distance between Particles (m)

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

1.) The current is doubled

2.) moving a magnet up and down near the wire

3.) An electric current in the wire produces a magnetic field.

4.) Distance between Particles (m)

Explanation:

1.) When 6 V battery is connected to a 24 ohm resistor to create a circuit, using ohms law, V = IR

Current I = 6/24 = 0.25 A

When the The 6 V battery is replaced with a 12 V battery,

Current I = 12/24 = 0.5 A

Therefore, The current is doubled

2.) Electric current will be induced when moving a magnet up and down near the wire

3.) An electric current in the wire produces a magnetic field.

4.) Distance between Particles (m)

The force of attraction between two different masses is inversely proportional to the square of the distance between them.

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3 years ago
which option below best explains why the second law of thermodynamics is not violated when heat flies from a cold freezer and in
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Explanation:

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3 years ago
If the current in a wire increases from 5 A to 10 A, what happens to its magnetic field? If the distance of a charged particle f
Anna007 [38]

(1) Doubling of the current through the wire will result in doubling of its magnetic  field.

The magnetic field around a wire is a function of the current I and radial distance r

B = \frac{\mu\cdot I }{2\pi r}

(with mu denoting the magnetic permeability of the medium). So, B is directly proportional to I. The field magnitude will double with the doubled current from 5A to 10A

(2) Using the same formula as in (1), we can see that the magnetic field is inversely proportional to the radial distance from the wire. So, a particle at 20cm will experience half the magnitude compared to a particle at 10cm.

(3) Answer

If a particle with a charge q  moves through a magnetic field B with velocity v, it will be acted on by the magnetic force

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2 years ago
Read 2 more answers
A vehicle of mass 1600kg take off from rest and coveres a distance of 280m in 60s. It continues at this speed for 98seconds and
Lady bird [3.3K]
1. V = Vo + a*t. 
<span>15 = 0 + a*5 a = 3 m/s^2. </span>

<span>2. V = Vo + a*t. </span>
<span>0 = 15 - 5*t, t = 3 s. </span>

<span>3. d1 = Vo*t + 0.5a*t^2. </span>
<span>Vo = 0, t = 5, a = 3 m/s^2, d1 = ?. </span>

<span>d2 = Vo*t. Vo = 15 m/s, t = 15 s, </span>
<span>d2 = ?. </span>

<span>V^2 = Vo^2 + 2a*d3. </span>
<span>V = 0, Vo = 15 m/s, a = -5 m/s^2, d3 = ?. </span>

<span>d1+d2+d3 = Total dist.</span>
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