Answer:
The value of impulse of the net force on the ball during its collision with wall is 
The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N
Explanation:
Mass of the ball = 0.5 kg
Horizontal velocity 
= 20 
Velocity after collision 
= - 10
(A). Impulse of the net force on the ball during its collision with wall is
I = 0.5 × (20 + 10)
This is the value of impulse of the net force on the ball during its collision with wall.
(B). The magnitude of average horizontal force
Where F = Force
I = impulse & t = time interval = 0.001 sec
F = 15000 N
This is the value of average horizontal force that the wall exerts on the ball during the impact.
Answer: 4.27 *10^6 N/C
Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:
E=k*x/(a^2+x^2)^3/2 where a is the ring radius and x the distance to the point measured from the center of the ring.
Replacing the data we have:
E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2
then
E=4.27 * 10^6 N/C
As the balls continue to accelerate to the ground, the distance between them before the first ball hits the ground will increase.
<h3>What is acceleration?</h3>
Acceleration is defined as the rate change of velocity with time.
acceleration a = (Δv) / (Δt)
Two identical heavy balls are dropped from the top of the Leaning Tower of Pisa. The second ball is dropped 1 s after the first ball. The first ball start falling 1s earlier than the second ball. Thus, the acceleration for first ball will be greater than the second ball.
Thus, the distance between them before the first ball hits the ground will increase.
Learn more about acceleration.
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