If measurements of gas are 75 L and 300 kIlopascals and then the gas is measured is second time and found to be 50 L, describe w
1 answer:
Answer:
The pressure must have increased in the process
Explanation:
The State Equation for gasses reads:
where P is the gas' pressure, V its volume, n the number of moles of gas, R the gas constant and T the temperature in degrees Kelvin.
If the temperature of the gas doesn't change in the described process, the right hand side of the equation stays the same. If that is the case, given that when the Volume of the gas diminishes from 75 liters to 50 liters, then the pressure must have increased to keep that product "P * V" constant:
So the pressure must have gone up to 450 kilopascals.
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Answer:
Original length = 2.97 m
Explanation:
Let the original length of the pendulum be 'L' m
Given:
Acceleration due to gravity (g) = 9.8 m/s²
Original time period of the pendulum (T) = 3.45 s
Now, the length is shortened by 1.0 m. So, the new length is 1 m less than the original length.
New length of the pendulum is,
New time period of the pendulum is,
We know that, the time period of a simple pendulum of length 'L' is given as:
-------------- (1)
So, for the new length, the time period is given as:
------------ (2)
Squaring both the equations and then dividing them, we get:
Now, plug in the given values and calculate 'L'. This gives,
Therefore, the original length of the simple pendulum is 2.97 m
The capacitance of the capacitor is
Explanation:
The capacitance of a parallel-plate capacitor is given by the equation
where
k is the dielectric constant of the medium
is the vacuum permittivity
A is the area of the plates
d is the separation between the plates
For the capacitor in this problem, we have:
k = 2.1 is the dielectric constant
is the separation between the plates
(I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)
Therefore, the capacitance of the capacitor is
Learn more about capacitors:
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