If measurements of gas are 75 L and 300 kIlopascals and then the gas is measured is second time and found to be 50 L, describe w
1 answer:
Answer:
The pressure must have increased in the process
Explanation:
The State Equation for gasses reads:
where P is the gas' pressure, V its volume, n the number of moles of gas, R the gas constant and T the temperature in degrees Kelvin.
If the temperature of the gas doesn't change in the described process, the right hand side of the equation stays the same. If that is the case, given that when the Volume of the gas diminishes from 75 liters to 50 liters, then the pressure must have increased to keep that product "P * V" constant:
So the pressure must have gone up to 450 kilopascals.
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Answer:
a
b
Explanation:
From the question we are told that
The pressure of the manometer when there is no gas flow is
The level of mercury is
The drop in the mercury level at the visible arm is
Generally when there is no gas flow the pressure of the manometer is equal to the gauge pressure which is mathematically represented as
Here is the density of mercury with value
and is the difference in the level of gas in arm one and two
So
Generally the height of the mercury at the arm connected to the pipe is mathematically represented as
=>
Generally from manometry principle we have that
Here is the pressure of the gas
converting to psig