1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivolga24 [154]
3 years ago
13

A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0

cm from the center of the ring.
Physics
1 answer:
Grace [21]3 years ago
8 0

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

You might be interested in
Which of the following temperatures is the coldest? A) 5 degrees B)0 degrees C) -15 degrees D) -7 degrees
Tresset [83]
It’s c -15 degrees because it it has below O which is below freezing
4 0
3 years ago
Read 2 more answers
In a mail-sorting facility, a 2.50-kg package slides down an inclined plane that makes an angle of 20.0° with the horizontal. Th
lawyer [7]

Answer:

The coefficient of kinetic friction is 0.382.

Explanation:

Given:

Angle of inclination is, \theta=20.0°

Mass of package is, m=2.50\ kg

Initial speed of package is, u=2.00\ m/s

Final speed of the package at the bottom is, v=0\ m/s

Distance of travel along the incline is, d=12.0\ m

Acceleration due to gravity is, g=9.8\ m/s^2

Let the coefficient of kinetic friction be \mu.

Now, the frictional force will be acting along the incline but in the direction opposite to the direction of motion.

So, the net acceleration acting on the package will be up the incline and is equal to:

a=\mu g\cos\theta-g\sin\theta ----------------- 1

Now, using equation of motion, we have:

v^2-u^2=2ad\\\\0-(2.00)^2=2a(12.0)

Solving for 'a', we get:

-4.00=24.0a\\\\a=-\frac{4}{24}=-\frac{1}{6}\ m/s^2

Now, plug in the value of 'a' in equation (1). This gives,

\mu g\cos\theta-g\sin\theta=\frac{1}{6} ( Neglecting negative sign)

Plug in all the given values and solve for \mu. This gives,

9.8(-sin(20)+\mu cos(20))=\frac{1}{6}\\\\-0.342+\mu\times 0.94=0.017\\\\0.94\mu=0.342+0.017\\\\0.94\mu=0.359\\\\\mu=\frac{0.359}{0.94}=0.382

Therefore, the coefficient of kinetic friction is 0.382.

5 0
3 years ago
Bolt starts the race not moving, but then increased his speed until he reaches a top speed. Once Bolt reaches his top speed he m
LekaFEV [45]

Answer:

a

Explanation:

<u>In order to maintain speed, a moving object or person must move at a constant velocity</u>. Accelerating will increase the speed while decelerating will reduce the speed.

Hence, for Bolt to be able to maintain the top speed for a few seconds, he needs to move at a constant velocity.

The correct option is a.

7 0
2 years ago
Suppose your car is on a 5% grade, meaning that for every 100 m you travel along the road you raise or lower only 5 m in elevati
kvv77 [185]

Answer:

734.215N

Explanation:

First we calculate the angle that corresponds to a 5% slope using the Tan-1 function

\beta = tan-1(5%)=2.86

then we use the component that corresponds to the direction parallel to the road, additionally we must multiply by the gravity value to find the weight(g=9.81m/s^2)

Wx=M*g*sen(2.86)=1500kg*9.81*sen(2.86)=734.215N

8 0
3 years ago
Read 2 more answers
If a mass of .343 kg moves down a 5m ramp in 5.8 seconds, what is the velocity and KE developed by the moving mass
Soloha48 [4]

Velocity 0.86m/s

0.13J

Explanation:

Given parameters:

Mass = 0.343kg

distance = 5m

time taken = 5.8s

Unknown:

Velocity of mass = ?

Kinetic energy = ?

Solution:

Velocity is the rate of change of displacement with time. It is a vector quantity that shows magnitude and direction.

 Mathematically;

   Velocity = \frac{displacement}{time}

  Velocity  = \frac{5}{5.8 } = 0.86m/s

Kinetic energy is the energy due to the motion of a body. It is expressed mathematically as:

  Kinetic energy  = \frac{1}{2}  m v^{2}

m is the mass

v is the velocity

  Kinetic energy  = \frac{1}{2 }   x    0.343  x    0.86^{2} = 0.13J

learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

7 0
3 years ago
Other questions:
  • A motor with an input power of 100 Watts is connected to a flywheel . How long in units of hours must the motor operate to trans
    6·1 answer
  • zeros are always considered significant digits when they are to the left of the decimal point True or False
    11·2 answers
  • A 1.0-kg ball has a velocity of 12 m/s downward just before it strikes the ground and bounces up with a velocity of 12 m/s upwar
    6·1 answer
  • Which of the following BEST describes sports etiquette?
    12·1 answer
  • A man jogs at a velocity of 2.5 m/s west for 1,200 s. He then walks at a velocity 1.0 m/s east for 500 s and then stops to rest
    12·1 answer
  • What is the state of an object accelerating due to the force of gravity alone?
    8·1 answer
  • A tennis ball rolls off the edge of a table. the table is 0.55m tall and the tennis ball lands 0.12m away from the table.
    14·1 answer
  • Which one of the following statements does not accurately describe the diatonic scale as it corresponds to the setup on a piano
    14·2 answers
  • A 15 kg mass is lifted to a height of 2m. What is gravitational potential energy at this position
    9·2 answers
  • I need help with problem C, finding the area of the accel. v time graph
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!