Hi
f(x) = g(x) if -x²+3x-2 - ( -x+1) = 0
-x² +3x-2 +x-1 = 0
-x² +4x -3 = 0
To solve, tou have to use the general method of resolution of a quadratic fonction.
To determine if it's has a solution in R, let's calculate Δ
Δ = (4)² - 4 * (1) *(-3)
Δ = 16 +12
Δ= 28
as Δ≥ 0 so the function allow two solution within R
so S 1 = ( -4 +√28) / 2 S 2 = (-4 -√28 ) /2
S1 = ( -4 + 2√7) /2 S2 = (-4 - 2√7) /2
S1 = (2 (-2 +√7) /2 S2 2 (-2 -√7) /2
S1 = -2 +√7 S2 = -2 -√7
So the two function are equal twice. one for x = -2 +√7 and second x = -2-√7
Answer:
x can be cancelled
Step-by-step explanation:
we are given
Firstly, we will factor numerator and denominator
and then we can factor it
now, we can factor denominator
now, we can replace it
we can see that
both terms are having x common
so, x can be cancelled
So,
x can be cancelled
Answer:
-8
Step-by-step explanation:
-4 (1)^2 -(1) -3
-4-1-3=-8
the false statement is: the absolute value of a number can be negative.
the absolute value of a number is never negative
use one five dollar box then use 4 4 $ boxes then its five dollar boxes the rest of the way so it would be 59 5$ boxes then Four 4$ boxes
