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mote1985 [20]
3 years ago
15

Given sin θ = 3/5 what is sec θ?

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

5/4

Step-by-step explanation:

To do this you must know that by definition secant is:


sec(\theta)=\frac{1}{cos(\theta)}


Furthermore:

sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}


Based on this information we know that 3 = opposite and 5 = hypotenuse.  Assuming this is a right triangle we can determine the adjacent side by Pythagorean Theorem.

c^2=a^2+b^2

Where c is the hypotenuse, a is adjacent and b is opposite.  Therefore,

c^2=a^2+b^2\\\\a=\sqrt{c^2-b^2} \\\\a=\sqrt{5^2-3^2} \\\\a=4


And so the adjacent side of this triangle is 4.  Going back to the definition of secant we can now know that:

sec(\theta)=\frac{1}{cos(\theta)}=\frac{1}{\frac{4}{5}}=\frac{5}{4}

Talja [164]3 years ago
4 0

The correct answer is D 5/4 :)


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Answer: See the step by step explanation.

Step-by-step explanation:

a) First, Let P(n) be the statement that n! < n^n

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In this case the statement would be (n = 2): P(2) = 2! < 2^2

b) Now to prove this, let's complet the basis step:

We know that 2! = 2 * 1 = 2

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Therefore: 2 < 4

c)  For this part, we'll say that the inductive hypothesis would be assuming that k! < k^k for some k ≥ 1

d) In this part, the only thing we need to know or prove is to show that P(k+1) is also true, given the inductive hypothesis in part c.

e) To prove that P(k+1) is true, let's solve the inductive hypothesis of k! < k^k:

(k + 1)! = (k + 1)k!  

(k + 1)k!  < (k + 1)^k  < (k + 1)(k + 1)^k

Since k < k+1 we have:

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6 0
3 years ago
Can someone help me plz .. Use these lengths to find cos B, tan B, and sin B.
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Answer:

cos B = \frac{7}{25}

tan B = \frac{24}{7}

sin B = \frac{24}{25}

Step-by-step explanation:

In the right triangle, there are three sides and 2 acute angles

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  • Leg1 and Leg 2 ⇒ the sides of the right angle

The trigonometry functions of one of the acute angles Ф are

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  • cos Ф = adjacent leg/hypotenuse
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In Δ ACB

∵ ∠C is the right angle

∴ AB is the hypotenuse

∵ AC is the opposite side of ∠B ⇒ leg1

∵ CB is the adjacent side of ∠B ⇒ leg2

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∴ cos B = \frac{CB}{AB} , tan B = \frac{AC}{CB} , sin B = \frac{AC}{AB}

∵ CB = 7, AB = 25, AC = 24

∴ cos B = \frac{7}{25}

∴ tan B = \frac{24}{7}

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Answer:

<h2>length= 40cm</h2><h2>width= 120cm</h2><h2>Step-by-step explanation:</h2>

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