Answer: Geometric average return would be 0.10% and arithmetic average return would be 9.17%.
Step-by-step explanation:
Since we have given that
Returns are as follows:
7%, 25%, 175, -13%, 25% and -6%.
Geometric return is given by
![\sqrt[6]{(1+0.07)(1+0.25)(1+0.17)(1-0.13)(1+0.25)(1-0.06)}-1\\\\=\sqrt[6]{(1.17)(1.25)(1.17)(0.87)(1.25)(0.94)}-1\\\\=0.097\%=0.10\%](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B%281%2B0.07%29%281%2B0.25%29%281%2B0.17%29%281-0.13%29%281%2B0.25%29%281-0.06%29%7D-1%5C%5C%5C%5C%3D%5Csqrt%5B6%5D%7B%281.17%29%281.25%29%281.17%29%280.87%29%281.25%29%280.94%29%7D-1%5C%5C%5C%5C%3D0.097%5C%25%3D0.10%5C%25)
Arithmetic average return would be
Hence, geometric average return would be 0.10% and arithmetic average return would be 9.17%.
When x=-5, y=(1/5)*(-5)-1=-2, so the first order pair is (-5,-2)
when y=-1, -1=(1/5)x-1, (1/5)x=0, x=0, so the second ordered pair is (0, -1)
8.9
The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number
Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)
log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
(log(Nm) + 2*log(M/100))/log(2) + 1 = n
(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
7.910312934 + 1 = n
8.910312934 = n
So the ASTM grain size number is 8.9
If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458
Or about 2,400,000 grains per square inch.
Answer:
100cm
Step-by-step explanation:
the tenths of cm are 10,20,30 etc.
Answer:
-9
Step-by-step explanation:
