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MariettaO [177]
2 years ago
5

Help " anyone" plz ....

Chemistry
1 answer:
boyakko [2]2 years ago
5 0

Answer:

letter A. i hope this is correct answer

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Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t
solniwko [45]
Heart: Pumps blood through the body
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Stomach: Breaks down food into small particles
Lungs: Oxygenates blood
7 0
3 years ago
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How many grams of oxygen can be obtained from 250. grams of KCIO3?
guapka [62]

Answer:

Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.

Explanation:

3 0
2 years ago
Answer both 8 and 9 will give u brain list with explanation as well so don’t just answer
goldfiish [28.3K]

Answer:

8. the answer is B.

9. the answer is A.

Explanation:

Hello!

8. In this case, by bearing to mind that the limiting reactant is always completely consumed and the excess one remain as a leftover at the end of the reaction, we can also infer that as all the limiting reactant is consumed, it must determine the maximum amount of product as the excess reactant will hypothetically produce a greater mass than expected; thus, the answer to this question is B.

9. In this case, since the mole ratio of oxygen to water is 1:2, the following proportional factor is used to calculate the produced mass of water:

3molO_2*\frac{2molH_2O}{1molO_2}=6molH_2O

Thus, the answer is this case is A.

Best regards!

6 0
3 years ago
What is the volume of 2.268mol of oxygen gas at 35○C and 3.0atm?
Eduardwww [97]
The volume is 

3 x_{123}
6 0
3 years ago
A student heats a sample of Copper (II) sulfate in a crucible and records the data shown in the table. What is the complete form
liberstina [14]

Explanation:

Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.

Mass of sample (CuSO4 * nH2O)

= 152.00g - 128.10g = 23.90g.

Mass of water loss during heating

= 152.00g - 147.60g = 4.40g.

Molar mass of H2O = 18g/mol

Moles of H2O in sample

= 4.40g / (18g/mol) = 0.244mol.

Mass of anhydrous sample (CuSO4)

= 23.90g - 4.40g = 19.50g

Molar mass of CuSO4 = 159.61g/mol

Moles of CuSO4 in sample

= 19.50g / (159.61g/mol) = 0.122mol.

Since mole ratio of CuSO4 to H2O

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6 0
3 years ago
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