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Aleonysh [2.5K]
3 years ago
10

Why is the Meniscus important?

Chemistry
1 answer:
sergejj [24]3 years ago
7 0
It is important because it contributes to the movement of your knee
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Explain why we did not see distinct lines (like on an emission spectrum) when the metal salts were burned.
marysya [2.9K]

Actually when we burn metal salts, we cannot actually really see distinct lines to appear because in reality, they are not really visible to the human eye. There is only a certain range of wavelength of light that our eyes can see.

To state in other way, some metal salts will give off light which has wavelengths that are outside of the visible region of the electromagnetic spectrum.<span> </span>

6 0
3 years ago
2O POINTS AND BRAINLIEST!!! FAST ANSWER PLEASE!!!! I WILL FAIL THIS IF YOU DON'T HELP ME!!!!!!
Flauer [41]
 <span>1. 1 molecule of C6H12O6(dextrose sugar), 2 molecles of c2h6o (ethyl alcohol), 2 molecules of Co2 

2. 48 hydrogen atoms </span>
8 0
3 years ago
Read 2 more answers
Balance the following skeleton reaction in acidic solution (if the coefficient is 1, put 1; if the coefficient is 0, put 0) and
Mashcka [7]

Answer:

2 CrO42- + 3N2O + 10 H+ -----> 2Cr3+ + 6NO + 5H2O

Explanation:

2 CrO42- + 3N2O + 10 H+ -----> 2Cr3+ + 6NO + 5H2O

Oxidizing agent: -----------------------------> CrO42-

Reducing agent: ----------------------------> N2O

explanation:

in CrO4-2 oxdiation state of Cr = +6

in Cr+3 oxidation state = +3

+6 oxidation state changed from +3 it is reduction .

so CrO4-2 is oxidizing agent

atomatically

N2O should be reducing agent

7 0
3 years ago
The pollen grains move in water randomly because of
polet [3.4K]
A the collisions between water particles and polllen grains
6 0
2 years ago
The ΔHcomb value for anethole is -5539 kJ/mol. Assume 0.840 g of anethole is combusted in a calorimeter whose heat capacity (Cal
bonufazy [111]

Answer:

Final temperature of calorimeter is 25.36^{0}\textrm{C}

Explanation:

Molar mass of anethole = 148.2 g/mol

So, 0.840 g of anethole = \frac{0.840}{148.2}moles of anethole = 0.00567 moles of anethole

1 mol of anethole releases 5539 kJ of heat upon combustion

So, 0.00567 moles of anethole release (5539\times 0.00567)kJ of heat or 31.41 kJ of heat

6.60 kJ of heat increases 1^{0}\textrm{C} temperature of calorimeter.

So, 31.41 kJ of heat increases (\frac{1}{6.60}\times 31.41)^{0}\textrm{C} or 4.76^{0}\textrm{C} temperature of calorimeter

So, the final temperature of calorimeter = (20.6+4.76)^{0}\textrm{C}=25.36^{0}\textrm{C}

3 0
3 years ago
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