Answer: CO is a limiting reagent with regards to the Fe production.
Explanation:

Moles of CO = 
moles of 
According to reaction , 3 mole of CO reacts with 1 mole of
then , 0.4714 moles of CO will react with :
moles of
that is 0.1571 moles.
0.4714 moles of CO will react with 0.1571 moles of
which means that CO is present in limited amount acting as limiting reagent.
Mole remaining of
= 0.2673 mol - 0.1571 mol = 0.1102 mol
Hence, CO is a limiting reagent and
is an excessive reagent.
The vapor pressure is EQUAL TO the outside air pressure.
Explanation:
<em>An</em><em> </em><em>independent</em><em> </em><em>variable</em><em> </em><em>is</em><em> </em><em>defines</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>variable</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>changed</em><em> </em><em>or</em><em> </em><em>controlled</em><em> </em><em>in</em><em> </em><em>a</em><em> </em><em>scientific</em><em> </em><em>experiment</em><em>. </em>
In BaF₂ the solubility will decreases on adding NaF
the solubility will increases on adding HCl
<h3>SOLUBILITY OF BARIUM FLUORIDE</h3>
- Increase in temperature will increase the solubility of the solid.
- By adding NaF - decrease the solubility of BaF₂
- By adding HCl - increase the solubility of BaF₂
<h3>BARIUM FLUORIDE</h3>
- It is colourless solid that occur as rare mineral
- It is corroded by moisture
- It is used in window of IR spectroscopy
Hence the barium fluoride the solubility decreases on adding NaF and increases on adding HCl.
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The number of sigma and pi bonds are,
Sigma Bonds =
16 Pi Bonds =
3Explanation: Every first bond formed between two atoms is sigma. Pi bond is formed when already a sigma bond is there. While in case of Alkyne (triple Bond) there is one sigma and one pi bond already present, so the third bond is formed by second side-to-side overlap of orbitals, hence, a second pi bond is formed.
Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.