Let us assume that this molecule is 100 percent ionic. In that case, the charges are distinguished by a bond length.
h = Q × r
= (160 × 10⁻¹⁹ c) (127 × 10⁻¹² m) (10 / 3.336 × 10⁻³⁰ cm)
= 6.09 D.
The actual dipole moment is = 1.08 D
Therefore, the percent ionic character is,
= 1.08 D / 6.09 D × 100
= 17.7 %.
Answer:
well it might be 1.)Cadmium Fluoride CdF2 150.4078
2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403
3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714
Explanation:
Answer:
The chances of the offspting being pink is 50%
