Answer:
A) 15.5 mL
Explanation:
Given, Mass of oxalic acid = 0.3500 g
Molar mass of oxalic acid = 90.03 g/mol
The formula for the calculation of moles is shown below:
Thus,
According to the given reaction:
5 moles of oxalic acid react with 2 moles of potassium permanganate
Thus,
1 mole of oxalic acid react with 2/5 moles of potassium permanganate
0.0038876 mole of oxalic acid react with 
moles of potassium permanganate
Moles of potassium permanganate = 0.001555 moles
Also, considering:
Molarity = 0.100 M
So,
Volume = 0.01555 L
Also, 1 L = 1000 mL
So, volume = 15.5 mL
The answer:
<span>When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from ?? oC to 87°C
application of charles law
charle's law tells that
T1/ V1 = T2 / V2, T must be in kelvin
it is given that V1 = 3.6 L, V2 = 15.5 L,
T2= </span><span>87°C= 360.15 K
</span>
so to find T1, T1 =(T2 / V2) x V1
T1= (360.15 / 15.5) * 3.6= 83.64° K = - 190.15° C
Answer:To solve for time, divide the distance traveled by the rate. For example, if Cole drives his car 45 km per hour and travels a total of 225 km, then he traveled for 225/45 = 5 hours.
Explanation:
Answer:
PCl5 <-> PCl3 + Cl2
PCl5 decomposes into PCl3 and Cl2 according to the equation above. A pure sample of Pcl5 is placed in a rigid, evacuated 1.00 L container. The initial pressure of the PCl5 is 1.00 atm. The temperature is held constant until the PCl5 reaches equilibrium with its decomposition products. The figures below show the initial and equilibrium conditions of the system.
As the reaction progresses toward equilibrium, the rate of the forward reaction
A) increases until it becomes the same as the reverse reaction rate at equilibrium
B) stays constant before and after equilibrium is reached
C) decreases to become a constant nonzero rate at equilibrium
D) decreases to become zero at equilibrium
Explanation:
At equilibrium, both forward and backward reactions take place with constant speed.
The reaction will never cease.
Due to this reason chemical equilibrium is called dynamic in nature.
At equilibrium:
the rate of forward reaction = rate of backward reaction
As the reaction progresses toward equilibrium, the rate of the forward reaction decreases to become a constant nonzero rate at equilibrium.
Answer is option C).
A. Conducting a drug experiment which will harm lab rats
