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Rama09 [41]
3 years ago
8

PLEASE HELP ME PLEASE I'M BEGGING YOU

Chemistry
2 answers:
gulaghasi [49]3 years ago
6 0
Easy B particles is the anwser
Anit [1.1K]3 years ago
4 0
The answer is B charged particles
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How many moles of water are present in 55.1 g of H2O
Rashid [163]

Answer:

3.0585147719047385 is the answer

7 0
3 years ago
In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibri
V125BC [204]

The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M

Using ICE table:-

      Acetic acid  +  Isopentyl alcohol   ------>    Isopentyl acetate +  water

I         8M                   4M                                           0                           0

C        8-x                   4-x                                          +x                          +x                      

E        8-x                   4-x                                          +x                          +x

Equilibrium constant (Keq) = 4.2

On using the equilibrium expression -

Keq = [Product] / [Reactant]

Keq = x^2 / (8-x) (4-x )

4.2  =  x^2 / 32 - 8x - 4x + x^2

    x =  3.4

Concentration of acetic acid  = 8-x = 8-3.4 = 4.6M

Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M

Concentration of isopentyl acetate = x = 3.4M

Concentration of water = x = 3.4M

Learn more about equilibrium expression

brainly.com/question/14751091

#SPJ4

4 0
2 years ago
(a) a 0.2 m potassium hydroxide solution is titrated with a 0.1 m nitric acid solution. (i) balanced equation: (ii)what would be
Stells [14]

\text{KOH} (aq) + \text{HNO}_3 (aq) \to \text{KNO}_3 (aq) + \text{H}_2\text{O} (l)

The solution shall contain only \text{KNO}_3 (aq) (and water) at the equivalence point. Both potassium hydroxide and nitric acid exist as strong electrolytes. As a result,  \text{KNO}_3 (aq), the salt derived from a reaction between the two species would undergo hydrolysis of a negligible extent. This neutralization reaction therefore be neutral at the equilibrium point.

The question states that the solution is "titrated with a ... nitric acid solution" indicating that \text{HNO}_3 is added to the initially-basic solution. PH value of the solution would keep decreasing as the volume of the acid added increases. The final solution would be acidic as it contains not only water and \text{KNO}_3 (aq), but some \text{HNO}_3 as well. Bromothymol blue would therefore demonstrates a yellow color, the color it present in an acidic solution, at the end of the titration.

5 0
3 years ago
If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?
svp [43]
Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:

C1V1 = C2V2
(6.0M)(2.0mL) = C2(500.0mL)
Therefore, the final concentration, C2 = 0.024M.
4 0
3 years ago
Read 2 more answers
What is the main intermolecular force in H2CO?
aivan3 [116]
Dipole-dipole interactions, and London dispersion interactions
5 0
4 years ago
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