1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shepuryov [24]
3 years ago
8

Help please!!!!!!!!!!!!!

Physics
1 answer:
Nonamiya [84]3 years ago
4 0

Answer:

one of the answers is 4 but thats all I got

You might be interested in
If a car is traveling at a speed of 45 miles per hour, how far<br>can it travel in 40 minutes?​
dusya [7]

Answer:

30 miles

Explanation:

<u>Step 1:</u>

Divide -> 45/60= .75 miles/minute

<u>Step 2:</u>

Multiply -> .75 x 40= 30

3 0
3 years ago
Read 2 more answers
Which of the following formulas is used to solve for current flowing through an electrical circuit? A. current = voltage ÷ resis
Alex787 [66]
The answer to your question is a

8 0
4 years ago
Read 2 more answers
Sound waves cannot carry energy through. A water B air C a mirror D a vacuum
Ber [7]
I looked up the question and got D- a vacuum
3 0
3 years ago
Heat is added to a 2kg piece of ice at a rate of 793kW. How long will it take for ice to melt if it was initially 0?
Ede4ka [16]

Answer:

0.84 s

Explanation:

Step 1

Given information:

Mass of the ice (m) = 2.0 kg

Heat transfer rate (Q/T) = 793.0 kW

Latent heat of fusion of ice (Lf) = 334 kJ/kg

\frac{Q}{T}  =  \frac{mLf}{T}

Substituting the corresponding values we have:

793.0 kW=  \frac{2.0kg(334 kJ/kg)}{T} \\  T  =  \frac{2.0kg(334 kJ/kg)}{793.0kW}  =  \frac{668kJ}{793kW}   \\  = 0.84s

8 0
3 years ago
A light ray moving from oil (n=1.38) into an unknown material. If the light is incident at 35 and refracts at 23, what is the in
Nastasia [14]

The index of refraction of the unknown material in which a ray of light is incident at 35° and refracted at 23° is 2.03

<h3>Snell's law</h3>

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

  • i is the angle of incidence
  • r is the angle of refraction
<h3>How to determine the refractive index </h3>

From the question given above, the following data were obtained:

  • Index of refraction of oil (nₒ) = 1.38
  • Angle of incidence (i) = 35°
  • Angle of refraction (r) = 23°
  • Index of refraction of unknown material (nᵣ) =?

nₒSine i = nᵣSine r

1.38 × Sine 35 = nᵣ × Sine 23

Divide both side by Sine 23

nᵣ = (1.38 × Sine 35) / Sine 23

nᵣ = 2.03

Thus, the index of refraction of the unknown material is 2.03

Learn more about Snell's law:

brainly.com/question/25758484

7 0
2 years ago
Other questions:
  • A car’s momentum is p when it is traveling with a velocity of v. If the velocity of that car doubles, what is the new momentum o
    5·2 answers
  • For a given amount of gas at a constant temperature, the volume of a gas varies inversely with its pressure is a statement of __
    6·1 answer
  • A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50 m/s. The goal is to have the cannonball t
    11·1 answer
  • Which group of components is common to the circulatory systems of most living animals? A. arteries, veins, capillaries B. vessel
    14·1 answer
  • What happens when light enters a pair of glasses
    7·1 answer
  • . In any energy transformation, energy is _____. destroyed created conserved
    12·2 answers
  • A 75.0-kg cross-country skier is climbing a 3.0° slope at a constant speed of 2.00 m/s and encounters air resistance of 25.0 N.
    11·1 answer
  • Two speakers in a stereo emit identical pure tones. As you move around in front of the speakers, you hear the sound alternating
    11·1 answer
  • In a given chemical reaction the energy of the products is less than the energy of the reactants which statement is true for thi
    12·1 answer
  • In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background sign
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!