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olga55 [171]
3 years ago
14

Why don’t we feel the gravitational pull of objects around us?

Physics
1 answer:
spayn [35]3 years ago
8 0
It is because gravity is not an independent force. Gravity comes as result of warped space time according to the theory of general relativity. Therefore we can’t feel gravity because it’s not a force that pulls or pushes.
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A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-
Alisiya [41]
First we need to convert the angular speed from rpm to rad/s. Keeping in mind that 
1 rev= 2 \pi rad
1 min = 60 s
the angular speed is
\omega = 7.18  \frac{rev}{min} \cdot  \frac{2 \pi}{60} = 0.75 rad/s

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s
3 0
3 years ago
Select the best answer.
KIM [24]

Answer:

C. Mantle

Explanation:

The Mantle is a thick layer of solid and partially melted rock

7 0
2 years ago
The new roller coaster at Carowinds flies along at 80 m/s. How long does it take to
Paha777 [63]
It takes about a really long time
4 0
3 years ago
A lever is used to lift a heavy rock. The mechanical advantage of the lever is 4 and the lever applies a force of 800 N to the r
Lesechka [4]
 The force applied to the lever is 400 N, because the force applied by the lever (800 N) divided by the mechanical advantage of the lever (4) equals
400 N.

(800/4) = 200
7 0
3 years ago
Un tubo de acero de 40000 kilómetros forma un anillo que se ajusta bien a la circunferencia de la tierra. Imagine que las person
Darina [25.2K]

Answer:

82.76m

Explanation:

In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.

You use the formula for the circumference of the steel ring:

C=2\pi r    (1)

C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)

you solve for r in the equation (1):

r=\frac{C}{2\pi}=\frac{4*10^7m}{2\pi}=6,366,197.724m

Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:

L=Lo[1+\alpha \Delta T]         (2)

L: final length of the tube = ?

Lo: initial length of the tube = 4*10^7m

ΔT = change in the temperature of the steel tube = 1°C

α: thermal coefficient expansion of steel = 13*10^-6 /°C

You replace the values of the parameters in the equation (2):

L=(4*10^7m)(1+(13*10^{-6}/ \°C)(1\°C))=40,000,520m

With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:

r'=\frac{C}{2\pi}=\frac{40,000,520m}{2\pi}=6,366,280.484m

Finally, you compare both r and r' radius:

r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m

Hence, the distance to the ring from the ground is 82.76m

4 0
3 years ago
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