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Sauron [17]
3 years ago
14

Find the volume of the cone. Either enter an exact answer in the terms of pi or use 3.14 for pi​

Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

37.7cm³

Step-by-step explanation:

pi×r² h/3

3.14×2² 9/3

=37.7cm³

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Use the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. Scale factor= 3 in:2m.
podryga [215]

Given:

The side of square = 12 in.

Scale factor of enlargement = 3 in : 2 m

To find:

The proportion that is use to solve the side length, x, of the enlarged square.

Solution:

Let, the side of length of enlarged square = x m

In case of enlargement the corresponding sides are proportional.

\dfrac{3}{12}=\dfrac{2}{x}

3x=2\times 12

3x=24

Divide both sides by 3.

x=\dfrac{24}{3}

x=8

Therefore, the required proportion is \dfrac{3}{12}=\dfrac{2}{x} and the side length of the square after enlargement is 8 m.

4 0
2 years ago
Each person in a ticket line gets either one or two tickets. You are the 51st person in line. Forty percent of the people in fro
Marrrta [24]
80 tickets have been given out

50*.4=20
50*.6=30
30*2=60
60+20=80
5 0
3 years ago
Help please and thank you ❤
Monica [59]

Answer:

In the pictures below

Step-by-step explanation:

8 0
2 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
2 years ago
Solve. 4 – d &lt; 4 + d<br> d &gt; 8<br><br> d &gt; 0<br><br> d &gt; –8<br><br> d &gt; –4
yaroslaw [1]

Answer:

-2d + 4 < 4

-2d < 0

d > 0

answer is b

3 0
2 years ago
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