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andreev551 [17]
3 years ago
11

Find mEC. 5x - 27) (2x - 5) D

Mathematics
1 answer:
UNO [17]3 years ago
4 0

Answer:

Arc EC = 58°

Step-by-step explanation:

First, find the value of x.

m<D = ½(arc EC) => Inscribed Angles Theorem

Substitute

2x - 5 = ½(5x - 27)

Multiply both sides by 2

2(2x - 5) = 5x - 27

4x - 10 = 5x - 27

Collect like terms

4x - 5x = 10 - 27

-x = -17

Divide both sides by -1

x = 17

Find arc EC:

Arc EC = 5x - 27

Plug in the value of x

Arc EC = 5(17) - 27 = 85 - 27

Arc EC = 58°

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If 4f(x)+f(5-x)=x2<br><br> What is f(x)?
aksik [14]
We are given that 4f(x)+f(5-x)=x^2.

Substitute x with 5-x, then the above equation becomes:

4f(5-x)+f(5-(5-x))=(5-x)^2, that is

4f(5-x)+f(x)=(5-x)^2


So, we have the following system of equations:

i) 4f(x)+f(5-x)=x^2
ii) 4f(5-x)+f(x)=(5-x)^2

multiply the first equation by -4, so that we eliminate f(5-x)'s

i) -16f(x)-4f(5-x)=-4x^2
ii) 4f(5-x)+f(x)=(5-x)^2

adding the 2 equations side by side we have:

-15f(x)=-4x^2+(5-x)^2

expanding the binomial, and collecting same terms we have:

-15f(x)=-4x^2+(25-10x+x^2)

-15f(x)=-3x^2-10x+25

dividing by -5:

3f(x)=\frac{3}{5}x^2+2x-5

dividing by 3:

\displaystyle{f(x)= \frac{1}{5}x^2+ \frac{2}{3}x-\frac{5}{3}


Answer: \displaystyle{f(x)= \frac{1}{5}x^2+ \frac{2}{3}x-\frac{5}{3}

6 0
3 years ago
Two metal disks, one with radius r = 2. 50 cm and the other with radius r = 5. 00 cm are welded together and
vova2212 [387]

The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.

<h3>What is moment of inertia?</h3>

Moment of inertia is the quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.

Using the formulas to calculate the moment of inertia of a solid cylinder:

I = ½MR²

Where;

I = moment (kgm²)

M = mass of object (Kg)

R = radius of object (m)

Total moment of inertia of the two disks is expressed as: I = I(1) + I(2)

That is;

I = ½M1R1 + ½M2R2

According to the provided information;

R1 = 2.50cm = 0.025m

M1 = 0.800kg

R2 = 5.00cm = 0.05m

M2 = 1.70kg

I = (½ × 0.800 × 0.025²) + (½ × 0.05² × 1.70)

I = (½ × 0.0005) + (½ × 0.00425)

I = (0.00025) + (0.002125)

I = 0.002375

I = 2.375 × 10-³ Kgm²

Hence The total moment of inertia of the two disks will be I = 2.375 × 10-³ Kgm² welded together to form one unit.

To know more about moment of inertia follow

brainly.com/question/14460640

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4 0
2 years ago
Which measurement would not be used to calculate the area of this triangle?
bonufazy [111]

Answer:

Im not sure but i think 2 is the answer

Step-by-step explanation:

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Artyom0805 [142]

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Step-by-step explanation:

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Fynjy0 [20]
Gina saw 25 monkeys 
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8 0
3 years ago
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