Answer:
There is an 85% probability that the sprinkler head will be activated.
Step-by-step explanation:
We have these following probabilities:
50% of the first sprinkler being triggered
90% of the first sprinkler being reliable
50% of the second sprinkler being triggered
80% of the second sprinkler being reliable.
What is the probability that the sprinkler head will be activated?

is the probability of the first sprinkler being triggered and activated. So:

is the probability of the second sprinkler being triggered and activated. So:


There is an 85% probability that the sprinkler head will be activated.
Answer:

Step-by-step explanation:
<h3>Derivative </h3>

Since, the derivative of e^x is e^x and e^(yx) is ye^(yx)
Y = 3x + b
Now plug in points
-7 = 3(-1) + b
-7 = -3 + b
b = -4
The y intercept is -4
Answer: Yes these triangles are similar
Step-by-step explanation:
First lets write down what we know just to make life easier
x=9
TL should be similar to CH
LY should be similar to KH
The angles should be equal due to SAS
So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14
So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14
Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5
Hope this helps.
Answer:
b=2
Step-by-step explanation:
-12+3b-1=-5-b
Combine like terms
-13 +3b = -5-b
Add b to each side
-13+3b+b = -5-b+b
-13+4b = -5
Add 13 to each side
-13+13 +4b = -5+13
4b = 8
Divide by 4
4b/4 = 8/4
b = 2