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professor190 [17]
3 years ago
12

Cameron wants to measure a poster frame, but he only has a sheet of paper that is 8 1/2 by 11 inches. He lays the long edge of t

he paper along the long edge of the frame several times and finds the frame is 3 papers long. How long is this in inches?
I'm helping my sisters' who's in 6th grade and I don't get the question. Hope you answer this!!! I'll put you as brainliest!
Mathematics
2 answers:
Mashcka [7]3 years ago
8 0
This would be 33 inches. the frame is 3 papers long when using the long end of the paper, which is 11 inches. 3 times 11 is equal to 33, so 33 inches would be the answer.
Paraphin [41]3 years ago
7 0

Answer:

The length will be 44 inches long.

Step-by-step explanation:

Since we have given that

Length of sheet of paper = 11 inches

Width of sheet of paper is given by

8\frac{1}{2}\ inches=\frac{17}{2}\ inches

According to question, he lays the long edge of the paper along the long edge of the frame several times and finds the frame is 4 papers long.

Since the long edge = 11 inches

So, its length becomes

4\times 11\\\\=44\ inches

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Answer:

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You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
MatroZZZ [7]

a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

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c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

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DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

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