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MaRussiya [10]
4 years ago
7

And observer reviews for identical objects that are traveling at speed close to the speed of light in their legs be used to rank

the objects according to their speeds A. No the Lankes of the four objects should be the same regardless of the speed B. Yes the shortest object is traveling the fastest C. Yes the longest object is traveling the fastest D. No the length of each object demands on the frame of reference of the observer
Physics
1 answer:
soldier1979 [14.2K]4 years ago
5 0

Answer:

C :)

Explanation:

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PLEASE ANSWER<br> PLEASE<br> PLEASE <br> HELP HELP<br> ASAP <br> ASAP <br><br> OWA OWA
Sliva [168]

Answer:

I think it might be (e

Explanation:

OWA OWA

8 0
3 years ago
Read 2 more answers
Now assume that the pitcher in Part D throws a 0.145-kg baseball parallel to the ground with a speed of 32 m/s in the +x directi
pogonyaev

Answer:

V2 = -25.93 m/s

Explanation:

First of all, we know that;

Momentum = mass x change in velocity

Thus;

Momentum = m(v2 - v1)

Also, we know that;

Impulse = force x time

And also that;

Momentum = Impulse

From the question, m = 0.145kg and V1 = 32m/s while impulse = -8.4 N.s

Thus;

0.145(v2 - 32) = -8.4

Now,

0.145v2 - 4.64 = -8.4

0.145v2 = -8.4 + 4.64

0.145v2 = -3.76

v2 = -3.76/0.145

= -25.931 m/s and to two significant figures gives -25.93 m/s

7 0
3 years ago
Estimate the monthly cost of using a 700-W refrigerator that runs for 10 h a day if the cost per kWh is $0.20.
slamgirl [31]

Power consumed by the refrigerator is given as

P = 700 W

Now if refrigerator is used 10 h a day then total usage of refrigerator for 1 month will be given as

t = 10 * 30 = 300 h

now the total energy consumed in one month is given as

E = P * t

E = 700 * 300

E = 210000

E = 210 kWh

now it is given that cost of one kWh is $0.20

then total cost of one month is given as

C = $0.20 * 210

C = $42


7 0
3 years ago
Can you travel faster by not running forward ?
GrogVix [38]
Yeah i think with a car or a plane:)
5 0
3 years ago
An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i
Butoxors [25]

Answer:5 m/s^{2}

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2} (1)

Where:

y=0m is the rock's final height

y_{o}=100 m is the rock's initial height

V_{o}=15 m/s is the rock's initial velocity

\theta=90\° is the angle at which the rock was thrown (directly upwards)

t=10 s is the time

g is the acceleration due gravity in Planet X

Then, isolating g and taking into account sin(90\°)=1:

g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t) (2)

g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s)) (3)

Finally:

g=5 m/s^{2} (4) This is the acceleration due gravity in Planet X

7 0
3 years ago
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