1) Molar composition
Base: 100 g
C: 40.00 g / 12.0 g /mol = 3.333 mol
H: 6.72 g / 1 g/mol = 6.72 mol
O: 53.28 g / 16g/mol = 3.33 mol
2) Divide by the smaller number of moles
C: 3.333 / 3.33 = 1.00
H: 6.72 / 3.33 = 2.02 ≈ 2
O: 3.33/3.33 = 1.00
3) Empirical formula
CH2O
molar mass of the empirical formula = 12 g/mol + 2*1g/mol + 16 g/mol = 30 g/,ol
4) Number of times that the mass of empirical formula is contained in the molar mass = 180 g/mol / 30 g/mol = 6
5) Molecular formula = 6 times the empirical formula
=>C6H12O6
Answer: C6H12O6
Answer:
answer is Proton.
Explanation:
because electron is too heavy and other one has no charge
Answer:
C
Explanation:
C3H8 + 502 ----> 3CO2 + 4H20.
