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inna [77]
4 years ago
7

What is the density of a solution that has a volume of 10.0 mL and a mass of 22 grams? 0.46 g/mL 4.5 g/mL 2.2 g/mL 0.22 g/mL

Chemistry
1 answer:
Goshia [24]4 years ago
5 0

Answer:

The density of this solution is 2.2 g/mL

Option 3 is correct

Explanation:

Step 1: Data given

Volume = 10.0 mL

mass = 22 grams

Step 2: Calculate the density

Density = Mass / volume

Density = 22.00 grams / 10.0 mL

Density = 2.2 grams / mL

The density of this solution is 2.2 g/mL

Option 3 is correct

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Mass is always conserved in a physical change. Energy may be released or absorbed when a substance changes from one physical state to another. In a chemical change, a chemical reaction yields a completely new substance. A substance's particles are changed during a chemical reaction.
5 0
4 years ago
1. (a) Write the two electrochemical half reactions for ethanol (C2H5OH) direct electrochemical conversion in a fuel cell with a
Natalka [10]

Answer:

(a) Two electrochemical half reactions for ethanol (C_{2}H_{5}OH) is written below

      C_{2}H_{5} + 60 ⇒ 2CO_{2} + 3H_{2}O + 12e^{-} (anode)

      3O_{2} + 12e^{-} ⇒ 60^{=} (Cathode)

(b) The direct oxidation of the fuel will occur in a solid oxide fuel cell but we have to compete with other sets of chemical electrochemical reaction such as water-gas-shift reaction

      CO + H_{2}O ⇆ CO_{2}  + H_{2}(WGSR)

(c) The electrochemical half reaction that could convert ethanol directly into a fuel cell that conducts hydrogen ions is shown below

C_{2}H_{5}OH + 3H_{2}O  ⇒  2CO_{2} + 12H^{+} + 12e^{-} (anode)

3O_{2} + 12H^{+} + 12e^{-} - 6H_{2}O (Cathode)

C_{2} H_{5} OH + 3O_{2}  ⇒  3H_{2}O + 2CO_{2}

(d) The half reactions that would be required are shown below

C_{2}H_{5} OH + 12OH^{-}  ⇒  CO_{2} + 9H_{2}O  + 12e^{-}  (anode)

3O_{2} + 6H_{2}O + 12e^{-}  ⇒  12OH^{-}  (Cathode)

C_{2}H_{5}OH + 3O_{2}  ⇒  3H_{2}O  + 2CO_{2}

8 0
4 years ago
The number of electrons in 1.6 gram CH, is:​
Alla [95]

Answer:

6.022 x 10²³ electrons

Explanation:

8 0
3 years ago
Read 2 more answers
Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid wat
Mashcka [7]

Answer:

0.26g of NaCl is the maximum mass that could be produced

Explanation:

Based on the reaction:

HCl + NaOH → NaCl + H₂O

<em>Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl</em>

<em />

To solve this question we need to find <em>limiting reactant. </em>The moles of limiting reactant = Moles of NaCl produced:

<em>Moles HCl -Molar mass: 36.46g/mol-:</em>

0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl

<em>Moles NaOH -Molar mass: 40g/mol-:</em>

0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH

As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.

The mass of NaCl is:

<em>Mass NaCl -Molar mass: 58.44g/mol-:</em>

0.0045 moles * (58.44g/mol) =

<h3>0.26g of NaCl is the maximum mass that could be produced</h3>
8 0
3 years ago
How many hybrid orbitals are found in CCl4? o one o two o three o four​
BlackZzzverrR [31]

Answer:

I Believe it is 4 orbitals s,p,p,p or aka sp^3

Explanation:

4 0
3 years ago
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